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2 years ago

11

My sister and I each brought a bottle of sunblock to the beach. My bottle had 89ml and my sister’s had 147ml. How much more sunb

lock did my sister have?

1 answer:

mariarad [96]2 years ago

7 0

Answer:

58 more ml

Step-by-step explanation:

147-89=58 ml.

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Kara and Steven are biking around a 1,800 kilometer path. They start biking from the same place, at the same time, and in the sa

levacccp [35]

It would take them 120 hours to get to the same point on the path again.

Kara is traveling at half the speed of Steven. Therefore, we Steven finishes his second lap Kara will just be finishing her first lap. They will both be at the starting lap again.

It will take Kara 120 hours to complete the lap.
1800 / 15 = 120

(That is a lot of time, do you have the numbers correct?)

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3 years ago

Lee records the height of players on a basketball team and calculates the mean absolute deviation of the set of data.

ladessa [460]

Answer:

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3 years ago

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

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3 years ago

A motorboat travels 244 kilometers in 4 hours going upstream and 749 kilometers in 7 hours going downstream. What is the rate of

Kryger [21]

Answer:

Speed of Motorboat = 84 kmph

Speed of Current = 23 kmph

Step-by-step explanation:

Distance Equation is:

D = RT

Where

D is distance

R is rate

T is time

Downstream rate is rate of boat PLUS current

Upstream rate is rate of boat MINUS current

Let rate of boat be "x" and rate of current be "c".

From first statement, we can write:

244 = (x - c)(4)

From second statement, we can write:

749 = (x + c)(7)

The first equation becomes:

244 = 4x - 4c

The second equation becomes:

749 = 7x + 7c

Multiplying first equation by 7 , we have:

7 * [244 = 4x - 4c] = 1708 = 28x - 28c

Multiplying 2nd equation by 4, we have:

4 * [749 = 7x + 7c] = 2996 = 28x + 28c

Now we add up these equations (in bold):

1708 = 28x - 28c

2996 = 28x + 28c

----------------------------

4704 = 56x

x = 4704/56

x = 84

Now using this value and plugging in original equation, we can find "c":

244 = 4x - 4c

244 = 4(84) - 4c

244 = 336 - 4c

4c = 92

c = 92/4

c = 23

<u>Speed of Motorboat = 84 kmph</u>

<u>Speed of Current = 23 kmph</u>

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3 years ago

How do you right a number in its prime factorization?

Whitepunk [10]

Please use "write" here, not "right." "write" is "right" here, if you get my drift.
"right" is wrong in this context. ;)

Example: Most of us would see immediately that 5 is a prime factor of 50.

Write 50 as 5 * 10.

10 is not prime; it can be factored into 5 and 2.

Thus, 50 written as the product of its prime factors is 5 * 5 * 2 (answer)

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3 years ago