The easiest way to do this is find the area of the large rectangle and subtract the two missing pieces. The length of the large rectangle is 24 and its height is 16. 24x16=384. The area is each of the two missing pieces is 2x2=4. Since there are two of them multiply by two 4x2=8. Then subtract eight from the first area calculated. 384-8=376 square meters

5 0

3 years ago

Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3

gayaneshka [121]

Answer:

E is not a subspace of $\mathbb{R}^2$

Step-by-step explanation:

E is not a subspace of $\mathbb{R}^2$

In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0

2 years ago