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pav-90 [236]
2 years ago
5

Summer school classes begin at 8:30 and last for two and a half hours. At what time

Mathematics
2 answers:
Afina-wow [57]2 years ago
8 0

Answer:

11:00

Step-by-step explanation:

8:30 + half an hour = 9:00

9:00 + 2 hours = 11:00

Luba_88 [7]2 years ago
7 0

Answer:it ends at 11:00

Step-by-step explanation:8:30+2:30=11:00

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M gets paid a set rate in his allowance for making his bed every morning. His rate is $0.50 earned for every morning that he mak
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Answer:

Step-by-step explanation:

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How do I solve number one so I can do the rest?
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multiply wtl

Step-by-step explanation:

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it is none since there is no relation

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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
After 4,000 gallons of water were added to a large water tank that was already filled to 3/4 of its capacity, the tank was then
dangina [55]

Answer:  The correct option is

(E) 80,000.

Step-by-step explanation:  Given that after adding 4,000 gallons of water to a large tank that was already filled to \dfrac{3}{4} of its capacity, the tank was then at \drac{4}{5} of its capacity.

We are to find the number of gallons of water that the tank hold when filled to capacity.

Let the tank can hold x gallons of water when filled to capacity.

Then, according to the given information, we have

\dfrac{3}{4}x+4000=\dfrac{4}{5}x\\\\\\\Rightarrow \dfrac{4}{5}x-\dfrac{3}{4}x=4000\\\\\\\Rightarrow \dfrac{16-15}{20}x=4000\\\\\Rightarrow x=4000\times20\\\\\Rightarrow x=80000.

Thus, the required capacity of the tank is 80,000 gallons of water.

Option (E) is CORRECT.

4 0
3 years ago
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