I'm assuming the dimensions are like the measures of whatever the figure is. Volume, length,width,height,circumference,radius,diameter,area,perimeter,etc. whatever you are working with, that will help you find the dimensions of the figure:)
Answer: 9 3/4 feet long
Explanation:
1 1/2 x 6 1/2 = 3/2 x 13/2 = 39/4 = 9 3/4 feet long
If you would like to know what is y when x = 42, you can calculate this using the following steps:
x = 8 ... y = 20
x = 42 ... y = ?
8 * y = 20 * 42 /8
y = 20 * 42 / 8
y = 105
The correct result would be: y = 105 when x = 42.
Answer:
9
Step-by-step explanation:
<span>Well, they couldnt have studied negative time.. So Id say the domain is \(x \ge 0\) where \(x\) is the time they studied.</span>
