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ad-work [718]
4 years ago
9

11. A hard-rubber or plastic comb rubbed against wool can often be shown to have a static charge. Why does a metal comb not read

ily show a static charge when rubbed against wool? Use 3 – 4 complete sentences in your answer.
Physics
1 answer:
Aneli [31]4 years ago
8 0
A hard rubber plastic comb is made out of rubber so it doesn't conduct electricity. This means that it is an insulator. Unlike a conductor (a metal comb), an insulator keeps the electrons at the place of where it was rubbed instead of equally distributing them around the surface of the comb.

In a metal comb, the charges within the comb move around while in the rubber comb they can't move around because in an insulator, it doesn't allow the movement of charges.
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Please help<br><br>SUVAT question.<br>answer + detailed explanation needed​
oee [108]

Answer:

4 s

-24.5 m/s

Explanation:

y = y₀ + v₀ t + ½ at²

v = at + v₀

where y is the final position,

y₀ is the initial position,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given:

y = 0 m

y₀ = 19.6 m

v₀ = 14.7 m/s

g = -9.8 m/s²

Find: t, v

Substitute values into the first equation and find t:

y = y₀ + v₀ t + ½ at²

0 = 19.6 + 14.7 t + ½ (-9.8) t²

0 = 19.6 + 14.7 t − 4.9 t²

0 = t² − 3 t − 4

0 = (t − 4) (t + 1)

t = -1 or 4

Since t must be positive, t = 4 seconds.

Now use the second equation to find v:

v = at + v₀

v = (-9.8) (4) + 14.7

v = -24.5

7 0
4 years ago
Electricity questions
egoroff_w [7]

Answer:

What Electricity questions?

Explanation:

5 0
3 years ago
Motion maps for two objects, Y and Z, are shown.
iragen [17]

Answer:

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3 years ago
A balloon filled with helium gas has an average density of rhob = 0.27 kg/m3. The density of the air is about rhoa = 1.23 kg/m3.
8_murik_8 [283]

Answer:34.84 m/s^2

   

Explanation:

Given

density of balloon \rho _{He}=0.27 kg/m^3

density of air \rho _a=1.23 kg/m^3

volume of balloon V=0.084 m^3

If balloon is rising then

F_b-mg=ma

where F_b=buoyant\ Force=\rho _a\times V\times g

mg=\rho _{He}\times V\times g=weight of gas

a=acceleration

\rho _a\times V\times g-\rho _{He}\times V\times g=\rho _{He}\times V\times a

\rho _a\times g-\rho _{He}\times g=\rho _{He}\times a

divide by \rho _{He}

\frac{\rho _a}{\rho _{He}}\times g-g=a

a=g(\frac{\rho _a}{\rho _{He}}-1)

a=g(\frac{1.23}{0.27}-1)

a=3.55\times 9.8

a=34.84 m/s^2

3 0
4 years ago
calculate the kinetic energy of a car with a mass of 500kg traveling at a velocity of 10m/s^2 north. A) 2,500j B) 25,000j C) 50,
Arte-miy333 [17]
The correct answer would be A) 2,500j
8 0
3 years ago
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