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sesenic [268]
4 years ago
7

Please helpSUVAT question.answer + detailed explanation needed​

Physics
1 answer:
oee [108]4 years ago
7 0

Answer:

4 s

-24.5 m/s

Explanation:

y = y₀ + v₀ t + ½ at²

v = at + v₀

where y is the final position,

y₀ is the initial position,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given:

y = 0 m

y₀ = 19.6 m

v₀ = 14.7 m/s

g = -9.8 m/s²

Find: t, v

Substitute values into the first equation and find t:

y = y₀ + v₀ t + ½ at²

0 = 19.6 + 14.7 t + ½ (-9.8) t²

0 = 19.6 + 14.7 t − 4.9 t²

0 = t² − 3 t − 4

0 = (t − 4) (t + 1)

t = -1 or 4

Since t must be positive, t = 4 seconds.

Now use the second equation to find v:

v = at + v₀

v = (-9.8) (4) + 14.7

v = -24.5

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The speed of a moving bullet can be deter-
Bad White [126]

Answer:

<em>v = 381 m/s</em>

Explanation:

<u>Linear Speed</u>

The linear speed of the bullet is calculated by the formula:

\displaystyle v=\frac{x}{t}

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x = Distance traveled

t = Time needed to travel x

We are given the distance the bullet travels x=61 cm = 0.61 m. We need to determine the time the bullet took to make the holes between the two disks.

The formula for the angular speed of a rotating object is:

\displaystyle \omega=\frac{\theta}{t}

Where θ is the angular displacement and t is the time. Solving for t:

\displaystyle t=\frac{\theta}{\omega}

The angular displacement is θ=14°. Converting to radians:

\theta=14*\pi/180=0.2443\ rad

The angular speed is w=1436 rev/min. Converting to rad/s:

\omega = 1436*2\pi/60=150.3776\ rad/s

Thus the time is:

\displaystyle t=\frac{0.2443\ rad}{150.3776\ rad/s}

t = 0.0016 s

Thus the speed of the bullet is:

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v = 381 m/s

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