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strojnjashka [21]
2 years ago
6

How much would you

Mathematics
1 answer:
Sophie [7]2 years ago
8 0
20000 ÷(1+4,75%)^20
=20000 ÷ 1,0475^20
=7905,86
You have to deposit $790586 today.
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Please help me -5x-3y=16 y=x
lilavasa [31]

Answer:

the answer is x=2 and y=2

Step-by-step explanation:

-3y=16+5x

-y=(16+5x)3

7 0
3 years ago
I need help with this pls
shtirl [24]

Answer:5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
7a-5b+4<br> a=2, b=3 and c=-6
KengaRu [80]

Answer: 3

Step-by-step explanation:

the statement given us:

7a-5b+4

a= 2

b= 3

so we have:

7*(2)-5*(3)+4

14-15+4 = 3

the answer is 3

6 0
3 years ago
PLS HELP ILL GIVE U BRAINLIST
SCORPION-xisa [38]
<h2>Answer:</h2>

B. |y| = 1.6

<h2>Step-by-step explanation:</h2>

A sketch of the vector is attached to this response.

As shown, the vector lies on the second quadrant and its horizontal and vertical components are given by x and y respectively.

Where;

|x| = v cos θ              -----------------(i)

|y| = v sin θ               -----------------(ii)

and

v = magnitude of the vector = 2.5km/hr

θ = angle that the vector makes with the +x axis = 90° + 50° = 140°

<em>To get the magnitude of the vector's vertical component</em>

<em>Substitute these values into equation(ii) as follows;</em>

|y| = 2.5 sin 140°

|y| =  2.5 x 0.6428

|y| = 1.607

|y| ≅ 1.6 km/hr

Therefore, the vertical component of the vector has a magnitude of 1.6 km/hr.

 

4 0
3 years ago
What is the remainder when (3x3 â€"" 2x2 4x â€"" 3) is divided by (x2 3x 3)?.
melamori03 [73]

The remainder of the equation is \rm 28x+30.

Given that,

When the equation \rm 3x^3-2x^2+4x-3 is divided by \rm x^2+3x+3.

We have to find,

The remainder of the equation?

According to the question,

The equation \rm 3x^3-2x^2+4x-3 is divided by \rm x^2+3x+3.

On the division of the polynomial, the remainder is,

\dfrac{\rm 3x^3-2x^2+4x-3}{\rm x^2+3x+3}

Factorize the equation to convert this into the simplest form,

\rm 3x^3-2x^2+4x-3\\\\3x^3-11x^2+9x^2+9x+28x-33x-33+30\\\\Taking \ the \ common \ terms \ and \ simplify\  the\  equation\\\\3x^3+9x^2+9x+11x^2+33x-33+28x+30\\\\3x(x^2+3x+3) - 11(x^2+3x+3) + 28x+30\\\\(3x+11) (x^2+3x+3) +28x +30

Now, the equation can be written as,

\rm = \dfrac{(3x+11) (x^2+3x+3) +28x +30}{ x^2+3x+3}\\\\=  \dfrac{(3x+11) (x^2+3x+3) }{ x^2+3x+3} + \dfrac{28x +30}{ x^2+3x+3}\\\\= (3x+11)   + \dfrac{28x +30}{ x^2+3x+3}\\\\

The relation between the divisor, remainder, and quotient is,

\rm = Quotient + \dfrac{Remainder}{Divisor}

On comparing with the equation,

The remainder becomes 28x +30.

Hence, The required remainder of the equation is \rm 28x+30.

For more details refer to the link given below.

brainly.com/question/25880057

7 0
3 years ago
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