All categories

3 years ago

Solve for x. 8(5 + x) = 11(9 + x) Answer as a fraction.

Mathematics

1 answer:

7nadin3 [17]3 years ago

8 0

distribute the 8 to the 5 and x. then distribute 11 to 9 and x.

(40+8x)=(99+11x)

-11x -11x

-3x+40=99

-40 -40

-3x= 59

divide three on both sides

x=59/-3

final answer x=-59/3

You might be interested in

The sum of X and 4 is greater than the difference of 2x and 3 find x

Sedaia [141]

Answer:

x = 7

Step-by-step explanation:

x + 4 > 2x - 3

x by itself = 1x

1x + 4 > 2x - 3

Subtract 1x

1x - 1x + 4 > 2x - 1x -3 =

4 > 1x -3

Add 3

4 + 3 > 1x -3 +3 =

7 > 1x

1x is the same as x

7 = x

8 0

3 years ago

What is the domain of the function

puteri [66]

Answer:

x∈R

Step-by-step explanation:

7 0

3 years ago

Let's find the sizes of unknown angles in the following figures.

liubo4ka [24]

Answer:

if this shape has greater that's obtuse

8 0

2 years ago

Select the correct answer.

Maru [420]

Answer:

Step-by-step explanation:

hdjdusvsbzbdhxusbeusishwbs

6 0

3 years ago

Read 2 more answers

I don't need you to work it out, just theorem(s) i need to reach the answer :)

VikaD [51]

Not sure why such an old question is showing up on my feed...

Anyway, let $x=\tan^{-1}\dfrac43$ and $y=\sin^{-1}\dfrac35$ . Then we want to find the exact value of $\cos(x-y)$ .

Use the angle difference identity:

$\cos(x-y)=\cos x\cos y+\sin x\sin y$

and right away we find $\sin y=\dfrac35$ . By the Pythagorean theorem, we also find $\cos y=\dfrac45$ . (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)

Meanwhile, if $\tan x=\dfrac43$ , then (by Pythagorean theorem) $\sec x=\dfrac53$ , so $\cos x=\dfrac35$ . And from this, $\sin x=\dfrac45$ .

So,

$\cos\left(\tan^{-1}\dfrac43-\sin^{-1}\dfrac35\right)=\dfrac35\cdot\dfrac45+\dfrac45\cdot\dfrac35=\dfrac{24}{25}$

7 0

4 years ago