Answer:
Explanation:
The following code is written in Java. It asks the user to enter the amount of change needed. This is done as a double since we are dealing with coins and not full dollar values alone. It then makes the necessary calculations to calculate the number of each coin needed and outputs it back to the user. A test case has been provided in the picture below with a sample output.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
int dollars = 1;
double quarters = 0.25;
double dimes = 0.10;
double nickels = 0.05;
double pennies = 0.01;
Scanner in = new Scanner(System.in);
System.out.println("Enter Change Value: ");
double change = in.nextDouble();
int numDollars, numQuarters, numDimes, numNickels, numPennies;
double newChange;
numDollars = (int) (change / dollars);
newChange = change % dollars;
numQuarters = (int) (newChange / quarters);
newChange = newChange % quarters;
numDimes = (int) (newChange / dimes);
newChange = newChange % dimes;
numNickels = (int) (newChange / nickels);
newChange = newChange % nickels + 0.001;
numPennies = (int) (newChange / pennies);
newChange = newChange % pennies;
System.out.println("Minimum Num of Coins needed: ");
if (numDollars != 1) {
System.out.println(numDollars + " Dollars");
} else {
System.out.println(numDollars + " Dollar");
}
if (numQuarters != 1) {
System.out.println(numQuarters + " Quarters");
} else {
System.out.println(numQuarters + " Quarter");
}
if (numDimes != 1) {
System.out.println(numDimes + " Dimes");
} else {
System.out.println(numDimes + " Dime");
}
if (numNickels != 1) {
System.out.println(numNickels + " Nickels");
} else {
System.out.println(numNickels + " Nickel");
}
if (numPennies != 1) {
System.out.println(numPennies + " Pennies");
} else {
System.out.println(numPennies + " Penny");
}
}
}
