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Diano4ka-milaya [45]
2 years ago
14

Find the volume of the triangular prism. 3.6 cm 5.4 cm 9 cm

Mathematics
1 answer:
MrMuchimi2 years ago
6 0

Answer:

174.96cm2

Step-by-step explanation:

V=lbh

=3.6×5.4×9

=174.96cm2

I don't knowif you want it in milliliters or litres so here are both of them

milliliters = 174.96

litres = 0.17496

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I don’t understand how to do this at all.
avanturin [10]

Answer:

2m

Step-by-step explanation:

(m+3) (m-1)

We need to FOIL

first m*m = m^2

outer -1*m  = -m

inner = 3m

last 3*-1 = -3

Add these together

m^2 -m +3m -3

m^2 +2m -3

3 0
3 years ago
Reflect the figure over the line <br> x<br> =<br> 2<br> x=2.
inessss [21]

2 = 2????

Thats what Im getting it from.

Since x is 2 then it would still be 2=2 in simple term.

7 0
3 years ago
If it takes 1/5 cup of flour to make 1/8 of a cake, how many cups of flour are needed to make a whole cake
Alexeev081 [22]

Answer:

D.) 1 3/5

Step-by-step explanation:

You need 1/5 cups of flour 8 times so you need to multiply 1/5 by 8.

1/5 × 8 = 8/5  

Then simplify.

8/5 = 5/5 + 3/5 = 1  3/5

3 0
3 years ago
Read 2 more answers
he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
Read 2 more answers
Marks test scores for this semester were 83,80,91,74,66,95,87,72,95,97 what is the mode of his test scores
Vlada [557]

Answer:

95

Step-by-step explanation:

Mode is what is the most frequent number that occurred; 95 occurred the most from the data.

3 0
3 years ago
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