Answer:
Δ BEC ≅ Δ AED
Step-by-step explanation:
Consider triangles BCA and ADB. Each of them share a common side, AB. Respectively each we should be able to tell that AD is congruent to BC, and DB is congruent to CA, so by SSS the triangles should be congruent.
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So another possibility is triangles BEC, and AED. As you can see, by the Vertical Angles Theorem m∠BEC = m∠ADE, resulting in the congruency of an angle, rather a side. As mentioned before AD is congruent to BC, and perhaps another side is congruent to another in the same triangle. It should be then, by SSA that the triangles are congruent - but that is not an option. SSA does is one of the exceptions, a rule that is not permitted to make the triangles congruent. Therefore, it is highly unlikely that triangles BEC and AED are congruent, but that is what our solution, comparative to the rest.
Δ BEC ≅ Δ AED .... this is our solution
6.5 ÷ 1345 = 0.0048 or 13/2690
Answer:
x = 2
Step-by-step explanation:
x ≠ 0
x ≠ - 2
x ≠ - 1
x = 2
Answer:
Step-by-step explanation:
The question presumes you have access to a computer algebra system. The one I have access to provided the output in the attachment. The list at the bottom is the list of the first four derivatives of f(x).
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The derivatives alternate signs, so (-1)^k will be a factor.
The numerators start at 17 and increase by increasing factors: 2, 3, 4, indicating k! will be a factor.
The denominators have a degree that is k+1.
Putting these observations together, we can write an expression for the k-th derivative of f(x):
Answer:
f(5)=12
Step-by-step explanation:
Replace all x by 5
f(5)=3(5)-2
multiply 3 and 5 together
f(5)=15-2
Simplify:
f(5)=13
Hope this helps!
