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2 years ago

Guys..please I really need you guys to help me please cause my hw will submit tomorrow

Mathematics

1 answer:

Rudik [331]2 years ago

3 0

A) 4. b) -4. c) 1. d) -2

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I need help with this now pls!!

zubka84 [21]

Answer:

first box 9.6 2nd box 7.2 third box 12

Step-by-step explanation:

9.6 is the missing height 12 is the hypotenuse is always last

6 0

2 years ago

The height of a wooden pole, h, is equal to 20 feet. A taut wire is stretched from a point on the ground to the top of the pole.

kykrilka [37]

ANSWER

D. 25 feet

EXPLANATION

The height of the wall,h, the taut wire and the distance from the base of the pole to the point on the ground, formed a right triangle.

According to the Pythagoras Theorem, the sum of the length of the squares of the two shorter legs equals the square of the hypotenuse.

Let the hypotenuse ( the length of the ) taught wire be,l.

Then

${l}^{2} = {h}^{2} + {b}^{2}$

${l}^{2} = {20}^{2} + {15}^{2}$

${l}^{2} = 400 + 225$

${l}^{2} = 625$

$l= \sqrt{625} = 25ft$

8 0

2 years ago

The ratio of the interior angles of a triangle is 2:3:5. What are the angle measures

Talja [164]

2:3:5
2x+3x+5x=180
10x=180
x=18
2x=36
3x=54
5x=90

6 0

2 years ago

Read 2 more answers

If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the

notsponge [240]

The area of the cross-section is 169 sq. cm.

That is the correct answer to this problem

5 0

2 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

2 years ago