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Eddi Din [679]
3 years ago
15

Guys..please I really need you guys to help me please cause my hw will submit tomorrow

Mathematics
1 answer:
Rudik [331]3 years ago
3 0
A) 4. b) -4. c) 1. d) -2
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Millimeter will be used to measure school bus
5 0
3 years ago
Find the size of each of 6 payments made at the end of each year into a 6% rate sinking fund which produces $82000 at the end of
Yuri [45]

Answer:

at the end of 1st year we pay $ 11756

at the end of 2nd year we pay $ 24217

at the end of 3rd year we pay $ 37426

at the end of 4th year we pay $ 51427

at the end of 5th year we pay $ 66269

at the end of 6th year we pay $ 82001

Step-by-step explanation:

Given data

rate ( i ) = 6%

Future payment  = $82000

no of time period ( n ) = 6

to find out

size of all of 6 payments

solution

we know future payment formula i.e.

future payment = payment per period ( (1 + rate)^{n} - 1 )   / rate

put all these value and get payment per period

payment per period = future payment × rate  /  ( (1 + rate)^{n} - 1 )   / rate

payment per period = 82000 × 0.06  /  ( (1 + 0.06)^{6} - 1 )   / rate

payment per period = 82000 × 0.06 / 0.4185

payment per period = $ 11756.27

at the end of 1st year we pay $ 11756

and at the end of 2nd year we pay $ 11756 × ( 1  + 0.06) + 11756

and at the end of 2nd year we pay $ 24217

and at the end of 3rd year we pay $ 24217 × ( 1  + 0.06) + 11756

and at the end of 3rd year we pay $ 37426

and at the end of 4th year we pay $ 37426 × ( 1  + 0.06) + 11756

and at the end of 4th year we pay $ 51427

and at the end of 5th year we pay $ 51427 × ( 1  + 0.06) + 11756

and at the end of 5th year we pay $ 66269

and at the end of 6th year we pay $ 66269 × ( 1  + 0.06) + 11756

and at the end of 6th year we pay $ 82001

4 0
3 years ago
Absolute value 2/3x -2/3 = 2/3
RideAnS [48]

Answer:

X=2

I really hope this helps!

5 0
3 years ago
Read 2 more answers
Type the correct answer in the box use nummerals instead of words. if necessary use / for the faction bar
zzz [600]

Answer: f(y) x g(y) = 1

Step-by-step explanation:

\frac{2y^3-y^2+2y-1}{y^3-y^2+y-1}\cdot \frac{2y^2-3y+1}{4y^2-4y+1}\\\\= \frac{4y^5-8y^4+9y^3-9y^2+5y-1}{4y^5-8y^4+9y^3-9y^2+5y-1} \\\\= \frac{(y-1)(2y-1)(2y-1)(y^2+1)}{(y-1)(2y-1)(2y-1)(y^2+1)} \\\\= 1

3 0
2 years ago
James, Gilbert, Matthew, and Simon ran in a relay race.
alexandr1967 [171]
Answer


You make all the denominators to 12.

That makes Gilbert the fastest and Simon the slowest.
4 0
3 years ago
Read 2 more answers
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