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2 years ago

(Help me pls as soon as possible this is due today!!!)

Mathematics

1 answer:

Gnesinka [82]2 years ago

4 0

1) 3:2

2) 3:2

3) 6:5

4)1:3

5) 3 feet

6) 56 correct answers

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How tall is the flagpole? X 6 ft 15 ft 4.5 ft

sweet-ann [11.9K]

Answer:

x = 20 ft

Step-by-step explanation:

We can use similar triangles and ratios to solve

4.5 ft 6 ft

--------- = ---------------

15 ft x ft

Using cross products

4.5x = 15*6

4.5x =90

Divide each side by 4.5

4.5x/4.5 = 90/4.5

x =20

3 0

3 years ago

The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i

Hunter-Best [27]

Answer:

$(x+3)^2+(y+11)^2=121$

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

Blue line is given by y = 4x + 1.
Point B is the center of the circle.
Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the general equation of the circle of radius lenght r centered at (h, k) is given by

$(x-h)^2+(y-k)^2=r^2$

then with h = -3, k = -11 and r= 11, the equation of our circle is

$(x+3)^2+(y+11)^2=121$

5 0

3 years ago

List all pairs of congruent angles

PSYCHO15rus [73]

Congruent angles of what... be more specific please..

8 0

3 years ago

Whay is -240 divided by -36

kherson [118]

7 because you have to round 6 to 7 from the former seven and seven is bigger than 4 so the 6 would become a

7

8 0

3 years ago

Read 2 more answers

Dy/dx of ln(x/x^²+1)

exis [7]

$\dfrac{dy}{dx}\ \ln\left(\dfrac{x}{x^2+1}\right)=\dfrac{1}{\frac{x}{x^2+1}}\cdot\dfrac{x'(x^2+1)-x(x^2+1)'}{(x^2+1)^2}\\\\=\dfrac{x^2+1}{x}\cdot\dfrac{1(x^2+1)-x(2x)}{(x^2+1)^2}=\dfrac{1}{x}\cdot\dfrac{x^2+1-2x^2}{x^2+1}=\dfrac{1-x^2}{x^3+x}\\\\Used:\\\\(\ln(x))'=\dfrac{1}{x}\\\\\left[f(g(x))\right]'=f'(g(x))\cdot g'(x)\\\\\left(\dfrac{f(x)}{g(x)}\right)'=\dfrac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}$

5 0

3 years ago