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3 years ago

Two wires

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

4 0

Answer:

am i suppoesd to do number 7 as well?

Step-by-step explanation:

Two wires

tether a balloon to the ground, as shown. How

high is the balloon above the ground? (Must Use Right

Triangle Trigonometry)

look at picture

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Sara and Jake shared a chocolate bar. Jake teased Sarah saying I have 4/8 of the candy bar you only have 2/4 of it. I have more

erma4kov [3.2K]

Answer:

im not 100% sure what your asking, but They do both have equal parts. because 4/8 is equal to 2/4

Step-by-step explanation:

8 0

3 years ago

= 3x +15 = 4x-10 What is the value of x?

Viefleur [7K]

Answer:

3x+15= 4x-10

3x-4x= -10-15

-x= -25(minus will be cut on both sides)

so x= 25

7 0

3 years ago

Jim is building a rectangular deck and wants the length to be 1 ft greater than the width. what will be the dimensions of the de

Travka [436]

Let x = width
x+1 is then the length

2x+2(x+1)=66
2x+2x+2=66
4x=64
x=16
deck will be 16x17, nice for a BBQ. :)

3 0

3 years ago

6(6v +6) - 5 = 1 + 6v Need answer with explaination

Tresset [83]

Answer:

v=-1

Step-by-Step Explanation:

6 0

3 years ago

Read 2 more answers

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

3 0

3 years ago