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storchak [24]
2 years ago
15

I will give you 100 points HELp

Mathematics
2 answers:
vladimir1956 [14]2 years ago
8 0

Answer:

CD = 26.0 cm (3 sf)

Step-by-step explanation:

<u>Sine Rule for side lengths</u>

\sf \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

(where A, B and C are the angles and a, b and c are the sides opposite the angles)

Find length BD:

\implies \sf \dfrac{AB}{\sin ADB}=\dfrac{BD}{\sin BAD}

\implies \sf \dfrac{12}{\sin 35^{\circ}}=\dfrac{BD}{\sin 90^{\circ}}

\implies \sf BD=\dfrac{12\sin 90^{\circ}}{\sin 35^{\circ}}

\implies \sf BD=20.92136155...cm

Find length CD:

\implies \sf \dfrac{BD}{\sin BCD}=\dfrac{CD}{\sin DBC}

\implies \sf \dfrac{20.921...}{\sin 52^{\circ}}=\dfrac{CD}{\sin 102^{\circ}}

\implies \sf CD=\dfrac{20.921...\sin 102^{\circ}}{\sin 52^{\circ}}

\implies \sf CD=25.96941667...cm

Therefore, CD = 26.0 cm (3 sf)

Naddika [18.5K]2 years ago
6 0

Answer:

CD ≈ 26.0 cm

Step-by-step explanation:

using the sine ratio in right triangle ABD

sin35° = \frac{opposite}{hypotenuse} = \frac{AB}{BD} = \frac{12}{BD} ( multiply both sides by BD )

BD × sin35° = 12 ( divide both sides by sin35° )

BD = \frac{12}{sin35} ≈ 20.92 cm

using the sine rule in Δ BCD

\frac{BD}{sinC} = \frac{CD}{sinB} , that is

\frac{20.92}{sin52} = \frac{CD}{sin102} ( cross- multiply )

CD × sin52° = 20.92 × sin102° ( divide both sides by sin52° )

CD = \frac{20.92sin102}{sin52} ≈ 26.0 cm ( to 3 significant figures )

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