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VladimirAG [237]
3 years ago
12

a total of 10000 was invested in two business ventures A and B .at the of the first year A and B yielded returns of 6% and 23÷4

respective on the original investment how was the original amount allocated if the total amount earned was 588.75?​
Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

(1)

compound amount = 802.5 $

invest earned = 52.5 $

Step-by-step explanation:

total amount = 10000 $

let amount x invested in ventures A and remaining (1000-x) on ventures B

now,

6x/100 +23/400(1000-x ) = 588.75

{24x+23(1000-x)}/400 =588.75

x=235500-230000

x=5500

Amount invested on A = 5500$

Amount invested on B = 4500$

(2)

principle=750$

time= 1 year

effective invest rate = 7%

a) compound amount = p(1+(r/w)^t

=750{1+(7/100)}^1

=802.5$

b) invest earned = 802.5-700 = 52.5$

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