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Answer: 34.64 m
Step-by-step explanation:
Given: A boat is 60 m from the base of a lighthouse.
The angle of depression between the lighthouse and the boat is 37°.
By using trigonometric ratios :
![\tan x=\dfrac{\text{Side opposite to }x}{\text{Side adjacent to }x}](https://tex.z-dn.net/?f=%5Ctan%20x%3D%5Cdfrac%7B%5Ctext%7BSide%20opposite%20to%20%7Dx%7D%7B%5Ctext%7BSide%20adjacent%20to%20%7Dx%7D)
here x= 37°, side opposite to x = height of lighthouse (h) , side adjacent to x = 60 m
![\tan 37^{\circ}=\dfrac{h}{60}\\\\\Rightarrow\ 0.57735=\dfrac{h}{60}\\\\\Rightarrow\ h= 60\times0.57735\approx34.64](https://tex.z-dn.net/?f=%5Ctan%2037%5E%7B%5Ccirc%7D%3D%5Cdfrac%7Bh%7D%7B60%7D%5C%5C%5C%5C%5CRightarrow%5C%200.57735%3D%5Cdfrac%7Bh%7D%7B60%7D%5C%5C%5C%5C%5CRightarrow%5C%20h%3D%2060%5Ctimes0.57735%5Capprox34.64)
Hence, the lighthouse is 34.64 m tall.
I would say 13 3/4 but dont take me for my word
Does it want it in standard form e.ge 0.00002 = 2 x 10(to the power of) -5, or is that in m and it wants you to convert it to micrometres?