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tia_tia [17]
2 years ago
15

Find the volume of the rectangular prism

Mathematics
1 answer:
ollegr [7]2 years ago
3 0

Answer:

10 1/2 cube Unites

Step-by-step explanation:

in volume you multiply them

5×1×4÷2=10

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Please help asap i will mark branlist
Serjik [45]

Answer:

C) Total Interest and Principal

Step-by-step explanation:

3 0
3 years ago
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An aquarium holds 11.35 cubic feet of water, and is 2.8 feet long and 1.5 feet wide. What is its depth? Round your answer to the
arlik [135]

Answer:

3 feet

Step-by-step explanation:

the volume of the aquarium is V= Lx wx H  

it is as of now given that V=11.25 cubic feet, so 11.25=LxWxH  

H tallness and it is the aquarium's profundity  

H=11.25/L xW= 11.25/2.5x1.5= 3 feet

7 0
2 years ago
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An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

8 0
3 years ago
Please help me with this one. <br> N° 15
Ivenika [448]
60° because its not hafe evin and 90° is hafe so its 60°
8 0
3 years ago
There are nine tennis balls and three cans what is the rate of number of tennis balls to number of cans
Gennadij [26K]

Answer:

That's a simple question.

Well, we know that the number of tennis ball are 9 which are to be put in 3 cans

So the  the rate of number of tennis balls to number of cans will be= number of balls/number of cans= 9/3


In order to find out the number of balls per can just simplify them= number of balls/number of cans =9/3 = 3 balls per can

So there will also be 3 tennis balls in one can


Read more on Brainly.in - https://brainly.in/question/1632700#readmore

Step-by-step explanation:


7 0
3 years ago
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