Ill mark brainlist plss help

Alexeev081 [22]

A( reduction
I don't know how to do B

3 0

3 years ago

Mark buys a wooden board that is 7 1/2 feet long. The cost of the board is $0.50 per foot, including tax. What is the total cost

artcher [175]

Answer:

Total cost of Mark's board is $3.75.

Step-by-step explanation:

We are given the following in the question:

Length of wooden board =

$=7\dfrac{1}{2}\text{ foot}$

Unit cost of board = $0.50 per foot

Total cost of board =

$=\text{Length of board}\times \text{Unit cost of board}\\\\=7\dfrac{1}{2}\times 0.50\\\\=\dfrac{15}{2}\times \dfrac{1}{2}\\\\=\dfrac{15}{4} = 3.75\$$

Thus, total cost of Mark's board is $3.75.

7 0

3 years ago

Someone please help and thx

gogolik [260]

Answer:

60 + 70n ≤ 200

Step-by-step explanation:

Since the $200 is a maximum, only inequalities with "≤ 200" make any sense in this context.

Since the unit rate for training sessins is $70, only expressions containing 70n make any sense in this context.

The only inequaity that makes any sense in this context is ...

60 + 70n ≤ 200

5 0

4 years ago

The center of a circle is at (−3, 1) and its radius is 9. What is the equation of the circle?

jek_recluse [69]

If a circle has center (a,b) and radius r, the equation is

$(x-a)^2+(y-b)^2=r^2$

So, you have

$(x+3)^2+(y-1)^2=81$

7 0

3 years ago

(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.

DaniilM [7]

Answer:

The answer is " $\frac{2}{9} \ and \ \frac{1}{9}$ "

Step-by-step explanation:

In point a:

The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They can pick 1 Chunin form of the matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They have the option to pick 1 join from of the country team with such a probability: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

And we can make the country teams: $3! = 6$ different forms. Its chances of choosing a team full in the process described also are:

$6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.$

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

Its odds of choosing the same rank ninja in such a different country team are: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

The likelihood of choosing the same level Ninja from the residual matter of national is: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$ Therefore, all 3 selected ninjas are likely the same grade: $3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}$

4 0

3 years ago

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