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Natasha_Volkova [10]

2 years ago

13

Find the solution to the system of equations. Y=2x+2

1 answer:

amm18122 years ago

7 0

Answer:

$(0, 2)$

Step-by-step explanation:

From the image (or by just looking at the equations and know what each part represents) you can tell the solution is (0;2)

Analitically, you already have them in a $y=\square$ form, so let's compare the two RHSs: $2x+2=-x+2 \rightarrow 3x=0 \rightarrow x=0$ . Let's replace the value in either to find $y=0$

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The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation

Olegator [25]

You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or 4k - 1 = 13. Then 4k = 14, and k = 14/4, or (after reduction) k = 7/2

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.

3 0

4 years ago

What is truncate in math?

Pavel [41]

Limiting the number of digits right of the decimal point

3 0

3 years ago

Find the sum.<br> 2x<br> x2 - 6x + 9 + x2 + 2x - 15

galina1969 [7]

Answer:

$\large\boxed{x^2-6x+9+x^2+2x-15=2x^2-4x-6}$

Step-by-step explanation:

$x^2-6x+9+x^2+2x-15\qquad\text{combine like terms}\\\\=(x^2+x^2)+(-6x+2x)+(9-15)\\\\=2x^2-4x-6$

5 0

3 years ago

Sarah is doing research on the average age of first-year resident physicians. She wants her estimate to be accurate to within 1

WINSTONCH [101]

Answer: The number of first-year residents she must survey to be 95% confident= 263

Step-by-step explanation:

When population standard deviation ( $\sigma$ ) is known and margin of error(E) is given, then the minimum sample size (n) is given by :-

$n=(\dfrac{z^*\sigma}{E})^2$ , z* = Two-tailed critical value for the given confidence interval.

For 95% confidence level , z* = 1.96

As, $\sigma$ = 8.265, E = 1

So, $n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]$

Hence, the number of first-year residents she must survey to be 95% confident= 263

7 0

3 years ago

A dealer earns a profit of 8$ per bag of white cement and a loss of 5$ per bag of grey cement.

Natali [406]

Answer :-

loss = <em> </em><em>100</em><em>0</em><em>$</em><em> </em>
4000

Step by step explanation :-

1#

Profit on 3000 bags of white cement sold = 3000 × 8 = 24000

loss on 5000 bags of grey cement sold = 5000 × 5 = 25000

<u>Alternatively</u><u>:</u><u> </u>

Net loss = ( 25000 - 24000 ) = 1000$
profit/ loss = $ [3000 × 8 - 5000 × 5 ]
$ [24000 - 25000]
-1000$

<em>As</em><em> </em><em>the</em><em> </em><em>result</em><em> </em><em>of</em><em> </em><em>transaction</em><em> </em><em>is</em><em> </em><em>negative</em><em>/</em><em> </em><em>loss</em><em> </em>

Loss = 1000$

2#

Loss on the scale of 6400 grey bags = 6400 × 5 = 32,000

<em>In</em><em> </em><em>order</em><em> </em><em>to</em><em> </em><em>have</em><em> </em><em>no</em><em> </em><em>profit</em><em>, </em><em> </em><em>profit from the </em><em>Cello </em><em>white cement should be 32</em><em>0</em><em>0</em><em>0</em><em>.</em><em> </em>

Number of white cement bags to be sold = 32000 / 8 = 4000

<em>4000 why cement bags and 6400</em><em> </em><em>grey</em><em> </em><em>cement</em><em> </em><em> </em><em>bags</em><em> </em><em>are sold in order to have no profit and </em><em>n</em><em>o</em><em> </em><em>loss </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>~</em>

5 0

2 years ago