The ladder, the wall and the floor form together a triangle rectangle, where the ladder is the hypotenuse of the triangle and the floor and wall are the cathetus. We know from Pythagoreas theorem that the square of the hypotenuse is equal to the sum of the two cathetus squared added, so we can write an equation with the data we have:
hyp^2 = cath1^2 + cath2^2
<span>hyp^2 = wall^2 + floor^2
</span>so we have the hypotenuse value, the floor value and the unknown is the wall height:
(22)^2 = wall^2 + (7)^2
484 = wall^2 + 49
wall^2 = 484 - 49 = 435
wall = √435
wall = 20.9
therefore the ladder touches the wall 20.9 feet above the ground
A = pi*r^2
(16/25)*pi = pi*r^2
16/25 = r^2
rt(16/25) = r
r = 4/5
C = 2pi*r
C = 2pi*(4/5)
C = (8/5) pi cm
Answer:
The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
Step-by-step explanation:
Let us consider the image attached.
Center of circle be O.
Arc AB subtends the angle
on the circle and
on the center of the circle.
To prove:

Proof:
In
: AO and PO are radius of the circles so AO = PO
And angles opposite to equal sides of a triangle are also equal in a triangle.
So, 
Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

Similarly,
In
: BO and PO are radius of the circles so BO = PO
And angles opposite to equal sides of a triangle are also equal in a triangle.
So, 
Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

Now, we can see that:

Using equations (1) and (2):

Hence, proved.