Answer:
- x = 4 is the only real zero
Step-by-step explanation:
<u>Find the zero's of f(x)</u>
- 2x³ - 12x² + 20x - 16 = 0
- x³ - 6x² + 10x - 8 = 0
- x³ - 4x² - 2x² + 8x + 2x - 8 = 0
- x²(x - 4) - 2x(x - 4) + 2(x - 4) = 0
- (x - 4)(x² - 2x + 2) = 0
- (x - 4)(x² - 2x + 1 + 1) = 0
- (x - 4)[(x - 1)² + 1] = 0
- x - 4 = 0 ⇒ x = 4, we already know this
- (x - 1)² + 1 = 0 ⇒ (x - 1)² = - 1, no real solution as the square is never negative
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Answer:
c
Step-by-step explanation:
i took a test on it
Answer:
C
Step-by-step explanation:
sorry if its wrong
