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Dafna11 [192]
3 years ago
9

Round to nearest hundred 452.0298

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:

500

Step-by-step explanation:

To determine whether the number rounds up or down, we look to the digit right of it. If it is 5 or bigger, we round up. In this case, we have exactly 5, so we round up to the nearest hundred, 500.

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William, Xing Mei, Yuki, and Zack run a race. In how many different ways can they finish?
BigorU [14]

Answer:

24

Step-by-step explanation:

Four total places someone can come - 1st, 2nd, 3rd or 4th. Anyone can come 1st - 4 people

Now only the remaining 3 can come second - 3 people

Next, only the remaining 2 people can come third - 2 people

Finally, one person comes last - 1 person

4 x 3 x 2 x 1 = 24

5 0
3 years ago
In contract negotiations between a local government agency and its workers,
Liono4ka [1.6K]

Answer:

a. 0.4

b. Not independent.

Step-by-step explanation:

a. We use the probability table attached below for our calculations.

-the probability that an agreement is reached on both sides is obtained from the table:

P(Agreement)=\frac{400}{1000}\\\\\\=0.4

b. To determine whether the two events are independent, we compare the probabilities P(s)\times P(i) and P(s \ and \ i) where i denotes insurance and s denotes salaries:

P(s)\times P(i)=0.5\times 0.7\\\\=0.35\\\\\\P(s \ and \ i)=0.4

Two events are considered to be independent, if and only if:

P(A).P(B)=P(A\ and \ B)\\\\=>P(s).P(i)\neq P(s\ and\  i)

Hence, the events are not independent.

8 0
3 years ago
A population has a mean muequals160 and a standard deviation sigmaequals20. Find the mean and standard deviation of the sampling
hoa [83]

Answer:

Mean 160

Standard deviation 2.63

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 160, \sigma = 20

Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 58.

Mean 160

Standard deviation s = \frac{20}{\sqrt{58}} = 2.63

6 0
4 years ago
If y=14 and x=8 what is x when y=30
Bumek [7]

Answer:

use so cratic it’s step by step app

Step-by-step explanation:

7 0
3 years ago
How do i do these two while using a proportion?
AnnZ [28]
For #2, the proportion would be .40/.25 and x/15, then you would cross multiply to find x. and for #3 the proportion would be 15/6 and 75/x and again you would cross multiply to find x. (:
7 0
3 years ago
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