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2 years ago

A 270 $ suit is marked down by %.20 Find the sale price.

Mathematics

1 answer:

Bond [772]2 years ago

7 0

Answer:

$216

Step-by-step explanation:

Do $\frac{20}{100}$ = 0.2. Now you do 270 x 0.2, which equals 54. Finnaly you do 270-54, which equals 216. So now you have your answer.

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What is the solution to the equation 1.6m − 4.8 = −1.6m?

Alla [95]

1.6m − 4.8 = −1.6m
- 1.6m -1.6m
 -4.8 = -3.2m

divide both sides by -3.2

m = 1.5

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2 years ago

At sea level, earths atmosphere exerts a pressure of 1 atmosphere. Atmospheric pressure P (in atmospheres) decreases with altitu

PtichkaEL [24]

Answer:

Initial Amount=1

Decay Factor=0.99987

Decay Rate=0.013%

Step-by-step explanation:

If P = 0.99987ᵃ

I. Initial amount

The initial amount is when a=0

P = 0.99987⁰ = 1

The Pressure at Sea Level=1

II. Decay factor

This is like the decay constant. From the model, P = 0.99987ᵃ, the decay constant/factor is 0.99987.

III. Decay Rate = 1-0.99987 = 0.00013

Expressed in Percentage = 0.013%

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2 years ago

Read 2 more answers

Which system of linear inequalities is represented by the graph?

MrRa [10]

Im not good in math and this is my first question, my best guess is D

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3 years ago

Read 2 more answers

I have finished the table but stuck in the question after...

lisov135 [29]

Answer:

7/48

Step-by-step explanation:

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7/48

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3 years ago

At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

4 0

3 years ago

A ​270 $ suit is marked down by ​%.20 Find the sale price.

A 270 $ suit is marked down by %.20 Find the sale price.