2 years ago

PRE-ALGEBRA DUE NOW! PLEASE HELP!

Mathematics

1 answer:

Nata [24]2 years ago

4 0

$\bold{FULL SOLUTION:}$

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Answer:

The sample size is $n = 451$

Step-by-step explanation:

From the question we are told that

The margin of error is E = 0.03

The sample proportion is $\^ p = 0.12$

From the question we are told the confidence level is 95% , hence the level of significance is

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=> $n = [\frac{1.96}{0.03} ]^2 *0.12 (1 - 0.12 )$

=> $n = 451$

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Solve the equation. 33 = p – 6.71 A. –39.71 B. –26.29 C. 39.71 D. 26.29

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