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3 years ago

A horizontal force of 20.8 N is applied to move a 425-kg cart a distance 0.636 m

Mathematics

1 answer:

juin [17]3 years ago

3 0

A work applied on the cart = 20.8x0.636

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Which is a solution for 3 > f? f = 7 f = 9 f= 3 f =2?

Fed [463]

Answer:

F = 2

Step-by-step explanation: If you want to know which one is a solution, you have to substitute the numbers in for F.

F = 7:

3 > f

3 > 7

This is false because 3 is NOT greater than 7, it is less than 7.

F = 9:

3 > f

3 > 9

This is false because 3 is NOT greater than 9, it is less than 9.

F = 2:

3 > f

3 > 2

This is TRUE because 3 IS greater than 2.

Hope this help you!!! :)

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3 years ago

A 6 sided die numbered 1 to 6 is rolled . Find the probability that in the roll of the results is an odd number or less than 4

stellarik [79]

Answer:

4/6 or 66%

Step-by-step explanation:

Odd numbers from 1 to 6 are: 1, 3, 5

Numbers less than 4 are: 1, 2, 3

So there are 4/ 6 possible outcomes.

So the probability is 4/6 or 66%.

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3 years ago

the sales price for a bicycle $315. the original price was first discounted by 5o% and then discounted by 10%. find the original

VMariaS [17]

Answer:

?× ( 1 − 50/ 100 ) × ( 1 − 10/ 100 ) = $ 315 ? = $ 315 /( .5 ) ( .9 ) = $ 700

Step-by-step explanation:

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2 years ago

What is the equation of the line that passes through the point (4,-7) and has a

aalyn [17]

Answer:

$y = -\frac{1}{2} x -5$

point slope form....

y - (-7) = -1/2(x-4)

y + 7 = -x/2 + 2

2y + 14 = -x + 4

2y = -x -10

y = -1/2 x - 5

Step-by-step explanation:

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2 years ago

On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th

Schach [20]

Answer:

Average speed is 37.35 mi/h

Step-by-step explanation:

given data

leave = 34 minutes before

church distance = 12.0 miles

average speed first 17 minutes = 5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × $\frac{17}{60}$

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

remaining distance Average speed = $\frac{distance}{time}$

Average speed = $\frac{10.584}{\frac{17}{60}}$

Average speed is 37.35 mi/h

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3 years ago