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3 years ago

A horizontal force of 20.8 N is applied to move a 425-kg cart a distance 0.636 m

Mathematics

1 answer:

juin [17]3 years ago

3 0

A work applied on the cart = 20.8x0.636

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I want to paint all three walls of the kitchen. One was a half cylinder. I want to paint the walls only not the ceiling. The wal

bearhunter [10]

Answer:

$490.9\ ft^{2}$

Step-by-step explanation:

we know that

The total area is equal to

$A=10(h)+2\pi r(h)+10(h)$

we have

$h=9\ ft$

$r=5.5\ ft$

$\pi=3.14$

substitute

$A=10(9)+2(3.14)(5.5)(9)+10(9)$

$A=490.9\ ft^{2}$

5 0

3 years ago

Which improper fraction is equal to the mixed number 6 4/7

Georgia [21]

Answer:

46/7 :)

Step-by-step explanation:

6 4/7 is the mixed number here.

The answer is (6*7 + 4) / 7 = 46/7 :)

5 0

3 years ago

Read 2 more answers

Apples cost $0.75 per pound and bananas cost $1.05 per pound.

dedylja [7]

Answer:

The baker bought 8 pounds of apples and 4 pounds of bananas.

Step-by-step explanation:

a+b=12.

0.75a+1.05b=10.20

First, multiply 2 my 10.

75a+105b=1020.

Then multiply 1 by 75.

75a+75b=900.

Then subtract.

75a+105b=1020

75a+75b=900.

75a-75a+105b-75b=1020-900

30b=120

b=4

Substitute into (1)

a+4=12

a=8.

Hope this helps :)

3 0

3 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

3 years ago

CAN SOMEONE HELP ASAP PLEASE!! I'll give 50 points to the person that's correct!

Gelneren [198K]

Choice 4 is incorrect. The angles aren’t similar nor congruent.

7 0

3 years ago