3 years ago

A horizontal force of 20.8 N is applied to move a 425-kg cart a distance 0.636 m

Mathematics

1 answer:

juin [17]3 years ago

3 0

A work applied on the cart = 20.8x0.636

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Which statement is correct?

Arisa [49]

Answer:

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

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Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-

2.3x10-5

7.69 x 10"

(2.06 x 10-2x1.88x10-)>

2.3x10-5

(2.06x 10-2X(1.88x 10-1)-7.69x104

2.3x10-5

Given that;

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

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Answer:

Step-by-step explanation:

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