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Strike441 [17]
1 year ago
5

There are 50 roses in a tray. There is at least 1 red rose among any 24 randomly selected roses, and there is 1 white rose among

any 28
randomly selected roses. How many white roses are there? QUICK PLS
Mathematics
1 answer:
VMariaS [17]1 year ago
8 0

So probability of red rose is 1/24

Probability of white rose is 1/28

TOTAL roses= 50

  • P(A)=(1/24)
  • P(B)=1/28=0.035
  • P(AUB)=1/50

P(A$\cap$ B)=1/24+1/28-1/50

  • 175+150-84/4200
  • 241/4200=0.057

So Probability of white is

  • 0.057-0.035
  • 0.022
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Answer:

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4  if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

n_{1}=n_{2}=12\\t-stat=-1.4

Compute the degrees of freedom as follows:

\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)

   =\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

P(t_{df}

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*Use a <em>t</em>-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

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