3 years ago

Solve for x. Round to the nearest tenth.

Mathematics

1 answer:

kondor19780726 [428]3 years ago

5 0

Answer:

22.8

Step-by-step explanation:

$a^{2} +b^{2} =c^{2} \\20^{2} +11^{2} =x^{2} \\400+121=x^{2}\\\sqrt{521} =x\\\\or\\\\22.8 = x$

You might be interested in

What is the domain of the function in this table?

Svet_ta [14]

Answer: B

Step-by-step explanation: The domain are all x values, meaning only the x values are counted for the domain.

8 0

3 years ago

Read 2 more answers

Please solve this question asap

disa [49]

Step-by-step explanation:

$y = \sqrt{4x + 6}$

${y}^{2} = 4x + 6$

${y}^{2} - 6 = 4x$

$\frac{1}{4} ( {y}^{2} - 6) = x$

Swap x and y

$\frac{ {x}^{2} - 6 }{4} = y$

3 0

2 years ago

What is an equation in pointelope form for the line that passes through the points (4. – 1) and (-3,0)

bulgar [2K]

Answer:

1/3

Step-by-step explanation:

2nd one

5 0

3 years ago

Jacob is showing his steps to solve the expression −27.8 ÷ 1 over 7.

salantis [7]

There is no error, Jacob did everything right :)

8 0

3 years ago

Read 2 more answers

What is the inverse of y=pi/2+sin x

Alekssandra [29.7K]

Answer:

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

Step-by-step explanation:

The given function is

$y=\frac{\pi}{2}+\sin x$

To find the inverse of this function, we interchange x and y.

$x=\frac{\pi}{2}+\sin y$

we now solve for y.

$x-\frac{\pi}{2}=\sin y$

Take the sine inverse of both sides to obtain;

$\sin ^{-1}(x-\frac{\pi}{2})=y$

Hence the inverse of the given function is;

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

where $\frac{\pi}{2}-1\le x\le \frac{\pi}{2}+1$

6 0

3 years ago

Read 2 more answers

Solve for x. Round to the nearest tenth. ​

Solve for x. Round to the nearest tenth.