3 years ago

Solve for x. Round to the nearest tenth.

Mathematics

1 answer:

kondor19780726 [428]3 years ago

5 0

Answer:

22.8

Step-by-step explanation:

$a^{2} +b^{2} =c^{2} \\20^{2} +11^{2} =x^{2} \\400+121=x^{2}\\\sqrt{521} =x\\\\or\\\\22.8 = x$

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Solve for x. Round to the nearest tenth. ​

Solve for x. Round to the nearest tenth.