3y = -2x + 2
y = x + 4 (Substitute the y)
3(x + 4) = -2x + 2 (Distribute)
3x + 12 = -2x + 2 (Add 3 to both sides)
+3x +3x
------------------------------------------
12 = 1x + 2 (Subtract 2 from both sides)
-2 - 2
------------------------
10 = 1x (Divide by 1 on both sides)
10/1 = 1x/1
x = 10
This is your x-coordinate
The answer is a i think but if u get it wrong im sorry
I’ll help you out, but what are the numbers in between? Like does it go boy 0, .3, .6, .9, to 1? Or is there a different pattern
Answer:
Step-by-step explanation:
Circle is centred at (0, -2)
-> h = 0 & k = - 2
radius of the circle (r) = y-coordinate of the center = - 2
Equation of circle in standard form is given as:
Plugging the values of h, k and r in the above equation, we find:
![(x-0)^2 +[y-(-2)]^2 = (-2)^2](https://tex.z-dn.net/?f=%28x-0%29%5E2%20%2B%5By-%28-2%29%5D%5E2%20%3D%20%28-2%29%5E2)
This is the required equation of circle.
