I need help to find the slope of graph.

Which of the following is being constructed in the image.

Sliva [168]

Answer:

3. a line perpendicular to a given line through a point not on the line

Step-by-step explanation:

The point not on the line suggests that choices 1 and 3 are possibilities. The fact that the dotted line is not parallel (and is perpendicular) to the solid line suggests that choice 3 is applicable and choice 1 is not.

The short arcs are equidistant from the end points of the chord that intercepts the larger arc. Hence the line through the crossing point of the short arcs and the point on the other side of the line will be the perpendicular bisector of the chord, and will be perpendicular to the solid line. Creating that perpendicular is likely the purpose of the construction.

5 0

3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

f a football player passes a football from 4 feet off the ground with an initial velocity of 36 feet per second, how long will i

saveliy_v [14]

When it hits the ground h = 0 so we have

-16t^2 + 36t + 4 = 0

t = 2.36 seconds to nearest hundredth.

4 0

3 years ago

Hey I need these by 8am or I'm screwed,

tiny-mole [99]

34.4 / 4 = 8.6

The value 214.01 is greater.

2.5 x 10^3 = 2,500

1 M = 100 CM
2 M = 200 CM
3 M = 300 CM
4 M = 400 CM
5 M = 500 CM
6 M = 600 CM
7 M = 700 CM

If you want detailed explanations after you get done with your classes ill be glad to explain. Happy studying!

5 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Match the polar equations to their rectangular forms.

LekaFEV [45]

The correct answer for the polar coordinates will be C, A, E, B, D

<h3>What is a polar coordinate system?</h3>

The polar coordinate system is a two-dimensional coordinate system in which a distance from a reference point and an angle from a reference direction identify each point on a plane. The pole is the reference point, and the polar axis is the ray from the pole in the reference direction.

The conversion relations between rectangular and polar coordinates can be used to find the polar coordinate equivalents. Those relations are ...

x = r·cos(θ)

y = r·sin(θ)

x² +y² = r²

x = 2

Using the expression for x, this is ...

r·cos(θ) = 2

r = 2/cos(θ) . . . . divide by cos(θ)

r = 2·sec(θ) . . . . use the trig identity

x²+y²=36

From above, this becomes ...

r² = 36

r = 6 . . . . . . take the square root

x²+y²=2y

From above, this becomes ...

r² = 2·r·sin(θ)

r = 2·sin(θ) . . . . . . divide by r

x=√3y

Using the above relations, this is ...

r·cos(θ) = √3·r·sin(θ)

1/√3 = sin(θ)/cos(θ) . . . . . . divide by √3·r·cos(θ)

tan(θ) = 1/√3 ⇒ θ = arctan(1/√3)

θ = π/6

x=y

From above, this is ...

r·cos(θ) = r·sin(θ)

1 = sin(θ)/cos(θ) = tan(θ) . . . . divide by r·cos(θ)

θ = arctan(1)

θ = π/4

However, the tangent function is periodic with period π, so θ = arctan(k)+π is also equivalent to the rectangular equation. It is the opposite ray, so forms the complete line when joined with the first ray.

To know more about polar coordinate system follow

brainly.com/question/14965899

#SPJ1

4 0

1 year ago

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