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SOVA2 [1]
2 years ago
5

Can someone please help with number 7

Mathematics
1 answer:
zepelin [54]2 years ago
6 0

Answer:

Step-by-step explanation:

h(t) = - 6 cos (πt/30) + 7

determine value of t when h(t) = 3

3 = -6 cos (πt/30) + 7

-4 = -6 cos (πt/30)

cos (πt/30) = 2/3

πt/30 = 0.841069rad or 2π - 0.841069rad [in first cycle]

t = 0.841069*30/π = 8.03s or

t = 30/π (2π - 0.841069) = 30/π (5.44211630718) = 51.97s

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Describe the end behavior of the given function <br> f(x)=9x^3-x^2-8x+6<br>​
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Find the surface area.
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side1=9ft

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6 0
3 years ago
A high percentage of people who fracture or dislocate a bone see a doctor for that condition. Suppose the percentage is 99%. Con
marishachu [46]

Answer:

(i) 0.15708

(ii) 0.432488

(iii) 3

Step-by-step explanation:

Given that, 99% of people who fracture or dislocate a bone see a doctor for that condition.

There is only two chance either the person having fracture or dislocation of bone will either see the doctor or not.

As per previous data, if one person got a fracture or dislocation of bone, the chance of seeing the doctor is 0.99. Assuming this chance is the same for every individual, so the total number of people having fractured or dislocated a bone can be considered as Bernoulli's population.

Let p be the probability of success represented by the chances of not seeing a doctor by any one individual having fractured or dislocated a bone.

So, p=1-0.99=0.01

According to Bernoulli's theorem, the probability of exactly r success among the total of n randomly selected from Bernoulli's population is

P(r)=\binom{n}{r}p^r(1-p)^{n-r}\cdots(i)

(i) The total number of persons randomly selected, n=400.

The probability that exactly 5 of them did not see a doctor

So, r=5 , p=0.01

Using equation (i),

P(r=5)=\binom{400}{5}(0.01)^5(1-0.01)^{400-5}

=\frac{400!}{(400-5)!\times 5!}(0.01)^5(0.99)^{395}

=0.15708

(ii) The probability that fewer than four of them did not see a doctor

=P(r

=P(r=0)+P(r=1)+P(r=2)+P(r=3)

=\binom{400}{0}(0.01)^0(0.99)^{400}+\binom{400}{1}(0.01)^1(0.99)^{399}+\binom{400}{2}(0.01)^2(0.99)^{398}+\binom{400}{3}(0.01)^3(0.99)^{397}

=0.017951+0.072527+0.146154+0.195856

=0.432488

(iii) The expected number of people who would not see a doctor

=np

=300\times 0.01

=3

7 0
3 years ago
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