One number: x
Its consecutive: x + 1
Product:
x(x+1)=121
x² + x - 121 = 0
Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485
As square root of 485 is not integer, do not exist two consecutive numbers with product of 121
Answer:
c = 6
Step-by-step explanation:
The compound inequality is c < x < 5
If we want a value of c such that there are no solutions, we need to make that inequality false.
From the inequality we can see that 5 must be greater than c to be true.
Therefore, we need to choose a value smaller or equal than 5.
For example, c=6.
If c = 6, that means that x is greater than 6 and smaller than 5. That's impossible, there is no number that meets that.
Therefore, our compound inequality 6 < x < 5 has no solutions.
The answer is: [B]: " -10a + 6b² − 4b + 3 " .
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Explanation:
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Given:
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-2(5a − 3b²) − 4b + 3 ;
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"Use the distributive property [of multiplication] to expand the expression."
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Note the distributive property of multiplication:
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a(b + c) = ab + ac ;
a(b − c) = ab − ac ;
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So, we have: " -2(5a − 3b²) − 4b + 3 " ;
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Start with: " -2(5a − 3b²) " ;
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-2(5a − 3b²) = (-2*5a) − (-2*3b²) = (-10a) − (-6b²)
= -10a + 6b²
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→ Now, bring down the rest of the problem;
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-10a + 6b² − 4b + 3 ; which is: Answer choice: [B].
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