2 years ago

Help...............!

Mathematics

1 answer:

Neporo4naja [7]2 years ago

5 0

Answer:

<h3>I had an advise that math antics can help u </h3>

Step-by-step explanation:

<h3>Thank you</h3>

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3 years ago

Please solve this for me.<br> Thanks

pav-90 [236]

Answer:

10y = 13x + 139

Step-by-step explanation:

Points (-5, -3) and (-15, -16) are the two points through which Line 1 passes.

So, the slope of the line 1 is $\frac{-3-(-16)}{-5-(-15)} =\frac{13}{10}$

Now, the slope of the parallel straight line i.e. line 2 will be same as line 1 i.e. $\frac{13}{10}$

Let us assume that the equation of line 2 is

$y= \frac{13}{10} x+c$ {Where c is a constant} ....... (1)

Now, line 2 passes through the point (-13, 17). Hence, this point will satisfy equation (1).

So, $17= \frac{13}{10} (-13)+c$

⇒ $c=\frac{139}{10}$

Therefore, the equation of line 2 will be

$y=\frac{13}{10} x+\frac{139}{10}$

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4 years ago