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givi [52]
1 year ago
12

HELPPP!! I’ll give brainliest

Mathematics
2 answers:
NemiM [27]1 year ago
7 0
40% should be the answer
Murljashka [212]1 year ago
7 0
If a dot its=10 persons then every sample which at least has one dot counts, which means 80%
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Connor went to the county fair with $32.50 in his pocket. He bought a hot dog and a drink for $4.50 and then
Alekssandra [29.7K]

Answer:

The answer is 14.

Step-by-step explanation:

4.50 + 2.00x ≤ 32.50

32.50 - 4.50 = 28

28 / 2.00 = 14

The total number of tickets he can buy is 14.

5 0
2 years ago
It takes one super giant pizza to feed three people if you invite 36 people how many peaches will you need
denis23 [38]
\bf \begin{array}{ccll}
\stackrel{super~duper}{pizza}&folks\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&3\\
p&36
\end{array}\implies \cfrac{1}{p}=\cfrac{3}{36}\implies \cfrac{1\cdot 36}{3}=p
8 0
3 years ago
PLS HELP ME WITH 3!<br><br> THANK YIU SO MUCH!!<br><br><br> (Random answers gets moderated.)
kirill115 [55]
6 {x}^{2} - 7x - 5 \\ 6 {x }^{2} + 3x - 10x - 5
3x(2x + 1) - 5(2x + 1) \\ (3x - 5)(2x + 1)
8 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
Paladinen [302]

Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

e^{C_1} =constant

So:

y(x)=C_1*sin(x)-3a

Finally, let's evaluate the initial condition in order to find C1:

y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a

Solving for C1:

C_1=4a\sqrt{3}

Therefore:

y(x)=4a\sqrt{3}* sin(x)-3a

3 0
3 years ago
For the month of January in a certain​ city, 42​% of the days are cloudy. Also in the month of January in the same​ city, 41​% o
zalisa [80]

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = P(A)=0.42

The probability that the days are cloudy and rainy = P(A\cap B)=0.41

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy  = 0.9762

7 0
3 years ago
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