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Bumek [7]
4 years ago
9

For the month of January in a certain​ city, 42​% of the days are cloudy. Also in the month of January in the same​ city, 41​% o

f the days are cloudy and rainy. What is the probability that a randomly selected day in January will be rainy if it is cloudy​?
Mathematics
1 answer:
zalisa [80]4 years ago
7 0

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = P(A)=0.42

The probability that the days are cloudy and rainy = P(A\cap B)=0.41

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy  = 0.9762

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stealth61 [152]

The equation of the circle is x² + y² = 25 and the transformation equation of the circle is x² + y² = 100.

<h3>What is the equation of the circle?</h3>

The following parameters are derived from the question:

(x - a)² + (y - b)² = r²

Center (a, b) = (0, 0)

Radius (r) = 5

Then the equation of the circle will be

x² + y² = 5²

x² + y² = 25

Then the transformation of the circle will be

Center (a, b) = (0, 0)

Radius (r) = 10

Then the equation of the circle will be

x² + y² = 10²

x² + y² = 100

More about the equation of circle link is given below.

brainly.com/question/10618691

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6 0
2 years ago
Juan got a new helicopter for Christmas and the time it takes to ascend to certain heights is shown above. His sister, Marla, be
Greeley [361]
Well for the first one, 
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For the second one you would have to find where they directly meet, I chose 40 and 20
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3 years ago
Use the commutative law of addition to write a equivalent expression ab+c
Scilla [17]

Answer:

c + ab

Step-by-step explanation:

The way an expression is written is the given you have presented to us.

The commutative law of addition would turn it around as

c + ab.

It just means change the order when adding. Not all systems allow this. It matters which way you put it in some systems.

5 0
3 years ago
A small regional carrier accepted 16 reservations for a particular flight with 12 seats. 8 reservations went to regular customer
wolverine [178]

Answer:

a) 32.04% probability that overbooking occurs.

b) 40.79% probability that the flight has empty seats.

Step-by-step explanation:

For each booked passenger, there are only two possible outcomes. Either they arrive for the flight, or they do not arrive. The probability of a passenger arriving is independent of other passengers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Our variable of interest are the 8 reservations that went for the passengers with a 48% probability of arriving.

This means that n = 8, p = 0.48

A) Find the probability that overbooking occurs.

12 seats, 8 of which are already occupied. So overbooking occurs if more than 4 of the reservated arrive.

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{8,5}.(0.48)^{5}.(0.52)^{3} = 0.2006

P(X = 6) = C_{8,6}.(0.48)^{6}.(0.52)^{2} = 0.0926

P(X = 7) = C_{8,7}.(0.48)^{7}.(0.52)^{7} = 0.0244

P(X = 8) = C_{8,5}.(0.48)^{8}.(0.52)^{0} = 0.0028

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.2006 + 0.0926 + 0.0244 + 0.0028 = 0.3204

32.04% probability that overbooking occurs.

B) Find the probability that the flight has empty seats.

Less than 4 of the booked passengers arrive.

To make it easier, i will use

P(X < 4) = 1 - (P(X = 4) + P(X > 4))

From a), P(X > 4) = 0.3204

P(X = 4) = C_{8,4}.(0.48)^{4}.(0.52)^{4} = 0.2717

P(X < 4) = 1 - (P(X = 4) + P(X > 4)) = 1 - (0.2717 + 0.3204) = 1 - 0.5921 = 0.4079

40.79% probability that the flight has empty seats.

4 0
3 years ago
I need this answer please
julsineya [31]

Answer:

3a+6b = 45

Multiply by 2

6a +12b = 90.....(1)

2a- 2b = -12

Multiply by 3

6a - 6b = -36 .....(2)

(1)-(2)

18b = 126

b= 7

3a+6b = 45

3a + 6(7) = 45

3a +42 = 45

3a = 3

a= 1

(a,b) = ( 1,7)

8 0
3 years ago
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