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Bumek [7]
3 years ago
9

For the month of January in a certain​ city, 42​% of the days are cloudy. Also in the month of January in the same​ city, 41​% o

f the days are cloudy and rainy. What is the probability that a randomly selected day in January will be rainy if it is cloudy​?
Mathematics
1 answer:
zalisa [80]3 years ago
7 0

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = P(A)=0.42

The probability that the days are cloudy and rainy = P(A\cap B)=0.41

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy  = 0.9762

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Total brain fart! 24+5x=-x+6(5a-4)
kow [346]

Answer:

When solving for x, answer = \large\boxed{x = 5a - 8}

When solving for a, answer = \large\boxed{a = 1/5x + 8/5}

Step-by-step explanation:

24 + 5x = -x + 6(5a - 4)

Start by multiplying 6 by the values in the parenthesis

24 + 5x = -x + 30a - 24

Add 24 to both sides of the equation

48 + 5x = -x + 30a

Add 1x to both sides of the equation

48 + 6x = 30a

Subtract 48 from both sides of the equation

6x = 30a - 48

Divide both sides of the equation by 6

x = 5a - 8 (Answer when solving for x)

Add 8 to both sides of the equation

x + 8 = 5a

Divide both sides of the equation by 5

a = 1/5x + 8/5 (Answer when solving for a)

-----------------------------------------

When solving for x, answer = \large\boxed{x = 5a - 8}

When solving for a, answer = \large\boxed{a = 1/5x + 8/5}

Hope this helps :)

3 0
3 years ago
Write an expression that is equivalent to 4n – 12 + 8y + (-3n).
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Answer:t+3

Step-by-step explanation:

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