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2 years ago

Solve the following equation:

Mathematics

1 answer:

stealth61 [152]2 years ago

8 0

Answer: Y=1/8

Slope m=0, b =1/8

Step-by-step explanation:

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PLEASE HELP ME IN ALGEBRA!! asap please :)

elena55 [62]

G(x)=3+2^x is the new equation

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3 years ago

A true-false test consists of 50 questions. how many does a student have to get right to convince you that he is not merely gues

umka2103 [35]

Hmmm. 20 or 30 so the teacher will count the rest,if a student guessed, wrong or right

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3 years ago

Sara says "If you subtract 11 from my number and multiply the difference by -3 , the result is -54 ." What is Sara's number?

KiRa [710]

Statement given :

→Sara says "If you subtract 11 from my number and multiply the difference by -3 , the result is -54 .

To find :

Sara's number

SOLUTION :

Let us take Sara's Number be “x”.

★According to Question,

→ x - 11×(-3)= -54

→ x + 33 = -54

→ x = -54-33

→ x = (-87)

let's verify our number,and check whether it's correct or not !

x - 11×(-3)= -54

Putting the value of x

(-87) - 11 × (-3)= -54

(-87) + 33 = -54

(-54) = -54

Hence, The L.H.S. = R.H.S.

Thus,our number is Verified.

6 0

3 years ago

A flea jumps from the ground to a height of 30 cm and travels 15 cm horizontally from where it started. Suppose the origin is lo

adelina 88 [10]

Answer:

$y=-\frac{8}{15}x^2+8x$

Step-by-step explanation:

Consider the equation that shows flea's motion is $y=ax^2+bx+c$ .

Since the origin is located at the point from where the flea jumped,

So, $y=ax^2+bx+c$ passes through (0,0).

That is, (0,0) must satisfy $y=ax^2+bx+c$ ,

$0=a(0)^2+b(0)+c$

$\implies c =0$

Now, it travels 15 cm horizontally from where it started.

That is, $y=ax^2+bx+c$ passes through (15,0).

$0=a(15)^2+b(15)+c$

$0=a(225)+b(15)$ (Because c=0)

$225a+15b=0$ ...... (1)

Again, it jumps from the ground to a height of 30 cm,

So, the y-coordinate of vertex of $y=ax^2+bx+c$ is 30.

Now, the x-coordinate of vertex of the quadratic function must be half of the distance from its starting point to final point.

That is, x-coordinate of the vertex = $\frac{15}{2}$ = 7.5,

Thus, vertex = (7.5, 30)

(7.5, 30) must satisfy $y=ax^2+bx+c$

That is, $30=a(7.5)^2+b(7.5)+c$

$30=56.25a+7.5b$

$56.25a+7.5b=30$ ...... (2)

Equation (1) - 2 × equation (2),

225a - 112.5a = -60

112.5a = -60

$\implies a = -\frac{60}{112.5}=-\frac{8}{15}$

From equation (1),

$225(-\frac{8}{15})+15b = 0$

$-120+15b=0$

$15b=120$

$b=8$

Substitute the values of a, b and c in the quadratic equation $y=ax^2+bx+c$ ,

$y=-\frac{8}{15}x^2+8x$

Which is the required quadratic equation.

6 0

3 years ago

Solve the inequality n/-3+ 8 > 6.

sleet_krkn [62]

Answer:

C.) n < 6

Step-by-step explanation:

Subtract 8:

n/-3 > -2

Multiply by -3. The negative multiplier requires the comparison be reversed:

n < 6

5 0

3 years ago