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2 years ago

(x + 7)^2 – 11 = 0 lesser = greater =

Mathematics

2 answers:

Andreyy892 years ago

4 0

Answer:

Lesser = - $\sqrt{11}$ - 7 = -10.317

Greater = + $\sqrt{11}$ - 7 = -3.683

Step-by-step explanation:

I am assuming you are asking for the lesser x solution and greater x solution.

(x + 7)^2 – 11 = 0

(x + 7)^2 = 11

x+7 = ± $\sqrt{11}$

x = ± $\sqrt{11}$ - 7

Lesser = - $\sqrt{11}$ - 7 = -10.317

Greater = + $\sqrt{11}$ - 7 = -3.683

PSYCHO15rus [73]2 years ago

4 0

Answer:

lesser= -14

greater= 0 (:

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BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

Step(i):-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

Step(ii):-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

verification :-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago

X = – 2y – 1 x = – 5y + 5

motikmotik

Answer:

x = -5

y = 2

Step-by-step explanation:

x = – 2y – 1

= -x - 2y - 1

-x - 2y = 1

x = – 5y + 5

= -x - 5y + 5

-x - 5y = -5

-x - 2y = 1

-x - 5y = -5

___________--

3y = 6

y = 6/3

y = 2

-x - 2y = 1

-x - 2(2) = 1

-x - 4 = 1

-x = 1 + 4

-x = 5

x = -5

6 0

2 years ago

Find the area of a circle is with a diameter of 6

m_a_m_a [10]

Answer:

28.27

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If f ( x ) f(x) is an exponential function where f ( − 3.5 ) = 25 f(−3.5)=25 and f ( 6 ) = 33 f(6)=33, then find the value of f

gavmur [86]

Given:

f(x) is an exponential function.

$f(-3.5)=25, f(6)=33$

To find:

The value of f(6.5).

Solution:

Let the exponential function is

$f(x)=ab^x$ ...(i)

Where, a is the initial value and b is the growth factor.

We have, $f(-3.5)=25$ . So, put x=-3.5 and f(x)=25 in (i).

$25=ab^{-3.5}$ ...(ii)

We have, $f(6)=33$ . So, put x=6 and f(x)=33 in (i).

$33=ab^{6}$ ...(iii)

On dividing (iii) by (ii), we get

$\dfrac{33}{25}=\dfrac{ab^{6}}{ab^{-3.5}}$

$1.32=b^{9.5}$

$(1.32)^{\frac{1}{9.5}}=b$

$1.0296556=b$

$b\approx 1.03$

Putting b=1.03 in (iii), we get

$33=a(1.03)^{6}$

$33=a(1.194)$

$\dfrac{33}{1.194}=a$

$a\approx 27.63$

Putting a=27.63 and b=1.03 in (i), we get

$f(x)=27.63(1.03)^x$

Therefore, the required exponential function is $f(x)=27.63(1.03)^x$ .

4 0

2 years ago

The double number line shows that 270270270 people attended this year's auction, which is 125\%125%125, percent as many people a

rodikova [14]

Using proportions, we have that:

125% of last year's attendance is of 270.

25% of last year's attendance is of 54.

100% of last year's attendance is of 216.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

We have that last year's amount is of x, and 125% of that is 270, hence:

1.25x = 270

x = 270/1.25

x = 216.

100% of last year's attendance is of 216.

25% of last year's attendance is given by:

0.25 x 216 = 54.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

3 0

1 year ago