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vampirchik [111]
2 years ago
9

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

ally, the failure rate for LED light bulbs that the company manufactures is 3%. Suppose a random sample of 10 LED light bulbs is selected. What is the probability that:
a. None of the LED light bulbs are defective?
b. Exactly one of the LED light bulbs is defective?
c. Two or fewer of the LED light bulbs are defective?
d. What are the mean and standard deviation of the binomial distribution for the number of defective LED light bulbs?
Mathematics
1 answer:
andrezito [222]2 years ago
6 0

Answer:

a) There is a 59.87% probability that none of the LED light bulbs are defective.

b) There is a 31.51% probability that exactly one of the light bulbs is defective.

c) There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) There is a 100% probability that three or more of the LED light bulbs are not defective.Step-by-step

explanation:

For each light bulb, there are only two possible outcomes. Either it fails, or it does not. This means that we use the binomial probability distribution to solve this problem.

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<span>A’(2, -4); B’(7, -9); C’(-2, -9)
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