Answer:
Step-by-step explanation:
The goal to solving any equation is to have x = {something}. That means we need to get the x out from underneath that radical. It's a square root, so we can "undo" it by squaring. Square both sides because this is an equation. Squaring both sides gives you
Get everything on one side of the equals sign and set the quadratic equal to 0:
Throw this into the quadratic formula to get that the solutions are x = 5 and -8. We need to see if only one works, both work, or neither work in the original equation.
Does 
?
and
and 5 = 5. So 5 works. Let's try -8 now:
and
so
-8 = 8? No it doesn't. So only 5 works. Your choice is the third one down.
Answer:
A) −3x + y = 3
B) 2x − y = −1 Adding both equations:
-x = 2
x = -2 y = -3
Step-by-step explanation:
I think d but im not sure
Correct Question:
Which term could be put in the blank to create a fully simplified polynomial written in standard form?
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y3)
Options
Answer:
Step-by-step explanation:
Given
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y%5E3)
Required
Fill in the missing gap
We have that:
From the polynomial, we can see that the power of x starts from 3 and stops at 0 while the power of y is constant.
Hence, the variable of the polynomial is x
This implies that the power of x decreases by 1 in each term.
The missing gap has to its left, a term with x to the power of 3 and to its right, a term with x to the power of 1.
This implies that the blank will be filled with a term that has its power of x to be 2
From the list of given options, only can be used to complete the polynomial.
Hence, the complete polynomial is:
Step 1 = Distributive Property ( multiplying the 2 by each term in parenthesis)
Step 2 = Addition Property ( adding like terms)
Step 3 = Addition Property (adding 34x to each side)
Step 4 = Division Property. ( dividing both sides by 17)
