All categories

2 years ago

Which unit of binary storage has a size that is processor dependent?.

Computers and Technology

1 answer:

mamaluj [8]2 years ago

7 0

It should be noted that the unit of binary storage has a size that is processor dependent is word.

<h3>What is binary storage?</h3>

In a binary storage , all the information that is been stored in a computer is usually done by following a sequence of 0's and 1's, .

Since the storage devices consist of a set of locations and do have one of two possible states.

learn more about binary storage at;

brainly.com/question/21400963

You might be interested in

given an array of integers a, your task is to count the number of pairs i and j (where 0 ≤ i < j < a.length), such that a[

Nimfa-mama [501]

Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.

<h3>Writting the code:</h3>

// C++ program for the above approach

#include <bits/stdc++.h>

using namespace std;

// Function to find the count required pairs

void getPairs(int arr[], int N, int K)

{

// Stores count of pairs

int count = 0;

// Traverse the array

for (int i = 0; i < N; i++) {

for (int j = i + 1; j < N; j++) {

// Check if the condition

// is satisfied or not

if (arr[i] > K * arr[j])

count++;

}

cout << count;

}

// Driver Code

int main()

{

int arr[] = { 5, 6, 2, 5 };

int N = sizeof(arr) / sizeof(arr[0]);

int K = 2;

// Function Call

getPairs(arr, N, K);

return 0;

}

See more about C++ code at brainly.com/question/17544466

#SPJ4

4 0

1 year ago

What can search the internet and select elements based on important words

Lana71 [14]

The item in question is known as a web search engine. These services will crawl websites and gather information about web pages to present to the searching user based on the search terms compared to the content of the webpage.

7 0

3 years ago

Parameters are treated as variables within a function.

Amanda [17]

Answer:

In C programming you can only pass variables as parameter to function.

Explanation:

3 0

3 years ago

Presentation software allows you to display information in the form of a slide show.

sammy [17]

Access is not presentation software. i use all 4

6 0

3 years ago

Write two methods: encrypt and decrypt. encrypt should #take as input a string, and return an encrypted version #of it according

Harman [31]

Answer:

The code is given below with appropriate comments

Explanation:

CIPHER = (("D", "A", "V", "I", "O"),

("Y", "N", "E", "R", "B"),

("C", "F", "G", "H", "K"),

("L", "M", "P", "Q", "S"),

("T", "U", "W", "X", "Z"))

# Add your code here!

def encrypt(plaintext):

theList = []

for char in plaintext:

if char.isalpha():

char = char.upper()

if char == "J":

char = "I"

theList.append(char)

if len(theList) % 2 == 1:

theList.append("X")

for i in range(0, len(theList), 2):

if theList[i] == theList[i + 1]:

theList[i + 1] = "X"

findex = [-1, -1]

sindex = [-1, -1]

for j in range(len(CIPHER)):

for k in range(len(CIPHER)):

if theList[i] == CIPHER[j][k]:

findex = [j, k]

if theList[i + 1] == CIPHER[j][k]:

sindex = [j, k]

# same row

if (findex[0] == sindex[0]):

findex[1] += 1

sindex[1] += 1

if findex[1] == 5:

findex[1] = 0

if sindex[1] == 5:

sindex[1] = 0

theList[i] = CIPHER[findex[0]][findex[1]]

theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

# same column

elif (findex[1] == sindex[1]):

findex[0] += 1

sindex[0] += 1

if findex[0] == 5:

findex[0] = 0

if sindex[0] == 5:

sindex[0] = 0

theList[i] = CIPHER[findex[0]][findex[1]]

theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

else:

theList[i] = CIPHER[findex[0]][sindex[1]]

theList[i + 1] = CIPHER[sindex[0]][findex[1]]

return "".join(theList)

def decrypt(ciphertext):

theString = ""

findex = [-1, -1]

sindex = [-1, -1]

for i in range(0, len(ciphertext), 2):

for j in range(len(CIPHER)):

for k in range(len(CIPHER)):

if ciphertext[i] == CIPHER[j][k]:

findex = [j, k]

if ciphertext[i + 1] == CIPHER[j][k]:

sindex = [j, k]

if (findex[0] == sindex[0]):

findex[1] -= 1

sindex[1] -= 1

if findex[1] == -1:

findex[1] = 4

if sindex[1] == -1:

sindex[1] = 4

theString += CIPHER[findex[0]][findex[1]]

theString += CIPHER[sindex[0]][sindex[1]]

# same column

elif (findex[1] == sindex[1]):

findex[0] -= 1

sindex[0] -= 1

if findex[0] == -1:

findex[0] = 4

if sindex[0] == -1:

sindex[0] = 4

theString += CIPHER[findex[0]][findex[1]]

theString += CIPHER[sindex[0]][sindex[1]]

else:

theString += CIPHER[findex[0]][sindex[1]]

theString += CIPHER[sindex[0]][findex[1]]

return theString

# Below are some lines of code that will test your function.

# You can change the value of the variable(s) to test your

# function with different inputs.

# If your function works correctly, this will originally

# print: QLGRQTVZIBTYQZ, then PSHELXOWORLDSX

print(encrypt("PS. Hello, worlds"))

print(decrypt("QLGRQTVZIBTYQZ"))

5 0

3 years ago