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polet [3.4K]
2 years ago
14

Triangle r q s is cut by line segment t v. line segment t v goes from side q r to side r s. the length of r v is x 10, the lengt

h of v s is x, the length of r t is x 4, and the length of t q is x minus 3. which value of x would make line segment t v is parallel to line segment q s? 3 8 10 11
Mathematics
1 answer:
CaHeK987 [17]2 years ago
5 0

The value of x that would make line segment T V is parallel to line segment Q S is where x = 10. (Option C)

<h3>What is a line segment?</h3>

In Mathematics, a Line Segment is a part of a line that has two endpoints.

The difference between a line segment and a line is that while the former has a starting and an endpoint, the latter does not. See the attached image.

<h3>What is the Step by Step solution to the above problem?</h3>

Step 1

Note that if QS is Parallel to TV, then both sides of the triangle must be proportionally divided by TV.

That is: RV/VS = RT/TQ.

Step 2 - replace the segments by the relevant equations

(X + 4)/(X- 3) = (X+10)/(X)

Step 3 - Cross Multiply

 x(x +4) = (x -3)(x +10)

Removing the parentheses, we have

 X² +4X = X² +7X -30; Subtract X² from both sides and we have;

4X = 7X - 30

<h3>Step 3 - Collect like terms by cross multiplying</h3>

-3X = -30 or

3X = 30

Divide both sides by three and we have:

X = 10

Learn  more about line segments at;
brainly.com/question/14366932
#SPJ4

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5 0
3 years ago
Which of the following are solutions?
zloy xaker [14]

This is a quadratic equation. There's a shortcut (two shortcuts really) called the Shakespeare Quadratic Formula (2b or -2b) applicable when the middle term is even:

x^2 - 2bx + c \textrm{ has zeros } x= b\pm \sqrt{b^2-c}

ax^2 - 2bx + c \textrm{ has zeros } x= \dfrac 1 a( \left b\pm \sqrt{b^2-ac} \right)

OK, our problem is

9x^2 - 6x -7 = 0

x = \frac 1 9 (3 \pm \sqrt{9-(9)(-7)}) = \frac 1 9(3 \pm \sqrt{72})= \frac 1 9(3 \pm 3 \sqrt{8}) = \frac 1 3(1 \pm \sqrt 8)

Typically we'd write \sqrt 8 = 2 \sqrt 2 but the answers here don't so we won't either.

Answer: C and D

7 0
3 years ago
Use a proportion to solve the problem. Round to the nearest tenth as needed. A triangle drawn on a map has sides of lengths 9 cm
Volgvan
X/15=101/9
x= 505/3
x= 168.3 
8 0
3 years ago
Answer fast ..................​
Kitty [74]

Answer:

Please check the explanation.

Step-by-step explanation:

Ascending Order:

When we talk about the numbers to be arranged in ascending order, it means the numbers need to be arranged from smallest to largest.

For example, if we have to arrange the numbers from 1 to 5 in ascending order.

It means, the ascending order will be: 1, 2, 3, 4, 5

Now, let us arrange the given numbers in ascending order.

a) 2234 to 2238         2234          2235            2236          2237          2238

b) 4099 to 4103          4099          4100             4101            4102          4103

c) 3298 to 3302          3298          3299            3300         3301           3302

d) 7269 to 7273          7269          7270            7271            7272          7273

e) 6354 to 6358          6354           6355           6356           6357          6358

f) 8379 to 8383           8379           8380            8381           8382          8383

g) 7365 to 7369          7365           7366           7367           7368          7369

5 0
3 years ago
Rewrite the function by completing the square. h(x)= 4 x^{2} -36 x +81
noname [10]

Answer:

4(x-4.5)^2

Step-by-step explanation:

h(x)=4x^2-36x+81

=4(x^2-9x)+81

=4(x^2-9x+20.25)-(4)(20.25)+81

=4(x-4.5)^2

6 0
3 years ago
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