Solution :
Given :
Sample mean, 
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with 
confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about 
that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.
Its 25.2 but what do u mean by that
Hey there,
All we have to do is 472-21=451
So your number would be 451
(1) -1.79, 2 1/4, 2.54 , -4
negative -> positive
reorder: -4. -1.79, 2 1/4 (or 2.25), 2.54
(2) -x
The larger x is the smaller the value
-$40.75<-$25.20
BUT the larger after the minus the more you owe so Renae owes more.
(3)
sorry idk
(4)
78F-x=70F
|x|=8*F
Answer:
The width of the yard is approximately 6 feet.
Step-by-step explanation:
1 cubic yard = 27 cubic feet. Then we must find the number of cubic yards.
So we know for 1 cubic yard = $98
And for "x" cubic yard = $58.07
1/x =98/58.07
x = 0.5925
After we figure this out we need to convert this into cubic feet
1 cubic yard = 27 cubic feet
0.5925 cubic yard = x cubic feet
1/0.5925= 27/x
x = 15 .99 cubic feet
So,
width x height x length = 16 cubic feet
w x 8 x (1/3) = 16
w = 48/8 = 6 feet
So:
The answer is:
The width of the yard is approximately 6 feet.
Hope this helps, have a good day. c;
