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2 years ago

13

I’m begging!! please someone help me with this

1 answer:

hammer [34]2 years ago

7 0

Step-by-step explanation:

I can use ur calculator to get the co ordinates

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Devi has a grid in the shape of a parallelogram. She has equilateral triangles. Each equilateral triangle has an area of 40 squa

katrin2010 [14]

The answer is 65
there are 10 millimeters in every centimeter...so to get the size of the grid, you multiply 260 x 10 to get 260 centimeters and then to see how many millimeters are in the 260 centimeter grid you multiply it by 260 by 10, which gives you 2,600 millimeters, so then all that is left to do is divide 2,600 millimeters by 40 millimeters for each of her 40 millimeter equilateral triangles to see how many will fit...the answer is 65 <span />

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3 years ago

Find an explicit solution to the Bernoulli equation. y'-1/3 y = 1/3 xe^xln(x)y^-2

NNADVOKAT [17]

$y'-\dfrac13y=\dfrac13xe^x\ln x\,y^{-2}$

Divide both sides by $\dfrac13y^{-2}(x)$ :

$3y^2y'-y^3=xe^x\ln x$

Substitute $v(x)=y(x)^3$ , so that $v'(x)=3y(x)^2y'(x)$ .

$v'-v=xe^x\ln x$

Multiply both sides by $e^{-x}$ :

$e^{-x}v'-e^{-x}v=x\ln x$

The left side can be condensed into the derivative of a product.

$(e^{-x}v)'=x\ln x$

Integrate both sides to get

$e^{-x}v=\dfrac12x^2\ln x-\dfrac14x^2+C$

Solve for $v(x)$ :

$v=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

Solve for $y(x)$ :

$y^3=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

$\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}$

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2 years ago

McKinley is 10 years less than half as old as Thomas. The sum of their age is 53. How old is each

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Step-by-step explanation:

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Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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3 years ago

Find an equivalent fraction for each. <br><br> Just do one answer

12345 [234]

Answer:

3/100=0.03.

second one.

60/10=6.

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2 years ago

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