1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timofeeve [1]
3 years ago
13

Paul Woonan, a self employed accountant, is married and enrolls in a non-group health insurance plan. The plan costs $7,710 per

year for the family coverage. What will he pay each month in premiums?
Mathematics
1 answer:
natulia [17]3 years ago
8 0

In this question, we're trying to find how much Paul will pay per month in premiums.

We know that the plan costs $7,710 for a year

In order to find his premium cost per month, we need to get the total price for the year and divide it by 12, since there are 12 months in a year.

Solve:

7,710 ÷ 12 = 642.5‬0

This means that he'll pay $642.5‬0 a month.

Answer:

$642.5‬0

You might be interested in
There are n machines in a factory, each of them has defective rate of 0.01. Some maintainers are hired to help machines working.
frosja888 [35]

Answer:

a) 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b) 1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c) ∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

Step-by-step explanation:  

Given that;

if n ⇒ ∞

p ⇒ 0

⇒ np = Constant = λ,  we can apply poisson approximation

⇒ Here 'p' is small ( p=0.01)

⇒ if (n=large) we can approximate it as prior distribution

⇒ let the number of defective items be d

so p(d) = ((e^-λ) × λ) / d!

NOW

a)

Let there be x number of repairs, So they will repair 20x machines on time. So if the number of defective machine is greater than 20x they can not repair it on time.

λ[n0.01]

p[ d > 20x ] = 1 - [ d ≤ 20x ]

= 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b)

Similarly in this case if number of machines d > 80x/3;

Then it can not be repaired in time

p[ d > 80x/3 ]

1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c)

n = 300, lets do it for first case i.e;

p [ d > 20x } ≤ 0.01

1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.01

⇒ ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.99

⇒ ∑²⁰ˣ_k=0 (λ^k)/k! = 0.99e^λ

∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

8 0
3 years ago
Pleaseee helpppp I really need it now please
lozanna [386]

Answer:

c = 60

Step-by-step explanation:

A triangle = 180 degrees

180-(15+105)=c

c=60

5 0
3 years ago
What is the area of a traingle with base as 2cm and height as 7cm?
Alex17521 [72]

Answer:

7 cm²

Step-by-step explanation:

Area of a triangle = (Base * hight)  / 2

A = (2* 7) /2 = 14/ 2 = 7 cm²

3 0
2 years ago
Read 2 more answers
How do you do part B of this question? Please help!!
posledela
All i know is that the equation of a straight line  is y=mx+c .......where m= gradient and c= the y intercept
3 0
3 years ago
Please help (10POINTS)
kobusy [5.1K]

Answer: it’s d

Step-by-step explanation: i did that

6 0
3 years ago
Other questions:
  • 4 9 16 25 36 nth term of the quadratic sequence
    14·1 answer
  • Anyone know this?? Will give brainliest and 50 pts!!!
    5·2 answers
  • Is 120% less than, more than or equal to 1
    5·1 answer
  • What is 1,296 divided by 36
    6·1 answer
  • Help me plz and explain
    5·1 answer
  • How knows how to do this? if so help me n give the answers.<br> needs to b done asap
    5·1 answer
  • Mark is mixing different color paints for a mural
    7·1 answer
  • 50 points, brainIiest, 5 stars, and a thanks. Please help me! :(
    7·2 answers
  • (1 x 3)+ (7 x 3) as a product of 2 factors
    10·1 answer
  • Please help me with this homework!
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!