The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

----------------(from equation 1)
----------------(given p=58 inches)




----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.





as,
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Answer: 9,364cm
Step-by-step explanation: 1 meter = 100 centimeters so it’s 93.64(100) = 9,364
Answer:
8^-2a^7 = a^7/8^2 = a^7/64
Step-by-step explanation:
Remember P.E.M.D.A.S
57 - 12 ÷ 4 · 3
= 57 - 3 · 3
= 57 - 9
= 48
Answer:
Union of inqualities:
x<7 or x>8
(not sure if this helps or not sorry!)