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attashe74 [19]
2 years ago
5

I need help on this please​

Mathematics
1 answer:
Anastaziya [24]2 years ago
6 0

Answer:

y=7/1x+26

Step-by-step explanation:

I didnt fully understand what the questions was asking. all I got from it was slope-intercept and even then it didn't make sense so I created the equation that goes throw those 2 points and added the y intercept to it.

hope this somehow helped...

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Which are linear pairs? Check all that apply.
boyakko [2]

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Options B, C and D

Step-by-step explanation:

Linear pair of angles means sum of the angles of the pair is 180° which are formed at a point of a line.

In other words, pair of supplementary angles is the linear pair.

From the figure attached,

Pair of the linear angles are,

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2). ∠BAE and ∠EAD

3). ∠EAD and ∠DAC

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5 0
3 years ago
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A 3-pound bag of bananas costs $2.88. What is the price per ounce?
Alborosie

Answer: 6 cents

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4 0
3 years ago
Find thhe remainder when 7^203 is divided by 4
Aleksandr [31]
Using the square-and-multiply approach, we have

7^{203}=7\times(7^{101})^2
7^{101}=7\times(7^{50})^2
7^{50}=(7^{25})^2
7^{25}=7\times(7^{12})^2
7^{12}=(7^6)^2
7^6=(7^3)^2
7^3=7\times7^2

and so, using the property that, if a_1\equiv b_1\mod n and a_2\equiv b_2\mod n, then a_1a_2\equiv b_1b_2\mod n, we get

7\equiv3\mod4
7^2\equiv9\equiv1\mod4
7^3\equiv7\times1\equiv7\equiv3\mod4
7^6\equiv9\equiv1\mod4
7^{12}\equiv1\mod4
7^{25}\equiv7\times1\equiv7\equiv3\mod4
7^{50}\equiv9\equiv1\mod4
7^{101}\equiv7\times1\equiv7\equiv3\mod4
7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4
4 0
3 years ago
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