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2 years ago

I need help on this please

Mathematics

1 answer:

Anastaziya [24]2 years ago

6 0

Answer:

y=7/1x+26

Step-by-step explanation:

I didnt fully understand what the questions was asking. all I got from it was slope-intercept and even then it didn't make sense so I created the equation that goes throw those 2 points and added the y intercept to it.

hope this somehow helped...

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Which statement about triangles is true

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3 years ago

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3 years ago

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Which are linear pairs? Check all that apply.

boyakko [2]

Answer:

Options B, C and D

Step-by-step explanation:

Linear pair of angles means sum of the angles of the pair is 180° which are formed at a point of a line.

In other words, pair of supplementary angles is the linear pair.

From the figure attached,

Pair of the linear angles are,

1). ∠BAC and ∠CAD

2). ∠BAE and ∠EAD

3). ∠EAD and ∠DAC

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3 years ago

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A 3-pound bag of bananas costs $2.88. What is the price per ounce?

Alborosie

Answer: 6 cents

Step-by-step explanation:

1 pound = 16 ounces

3 pounds = 48 ounces

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0.06 = 6 cents.

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Hope this helps!

4 0

3 years ago

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

4 0

3 years ago

I need help on this please​

I need help on this please