Answer:
To figure out the change, we subtract the original temperature by the following after temperature.
18°F - original
-9°F - subsequent time after original
So we set up the equation;
18°F - (-9°F)
(Two negatives combine to form a positive)
18°F + 9°F
= <u>27°F</u> was the change in temperature.
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
Answer:
3−y
2. 8
4.2bh
Step-by-step explanation:
5(2x+y)=15
2 Divide both sides by 55.
2x+y=\frac{15}{5}2x+y=
5
15
3 Simplify \frac{15}{5}
5
15
to 33.
2x+y=32x+y=3
4 Subtract yy from both sides.
2x=3-y2x=3−y
5 Divide both sides by 22.
x=\frac{3-y}{2}x=
2
1. 3−y
2. 8
2.Add 2y2y to both sides.
x=-8+2yx=−8+2y
2 Regroup terms.
x=2y-8x=2y−8
Your balance would be 35, I think
U can multiply on some answers but some are trick questions
