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irga5000 [103]
2 years ago
5

Rewrite the following expression using the properties of loy

Mathematics
2 answers:
andrew-mc [135]2 years ago
7 0

Answer:

\log_2\dfrac{x^2z}{y^2}+\log_9x^{12}y^4

Step-by-step explanation:

<u>Log laws</u>

\textsf{Product law}: \quad \log_axy=\log_ax + \log_ay

\textsf{Quotient law}: \quad \log_a\frac{x}{y}=\log_ax - \log_ay

\textsf{Power law}: \quad \log_ax^n=n\log_ax

Given expression:

\log_2z+2\log_2x+4\log_9y+12\log_9x-2\log_2y

Group terms with same log base:

\implies \log_2z+2\log_2x-2\log_2y+4\log_9y+12\log_9x

Apply the power law:

\implies \log_2z+\log_2x^2-\log_2y^2+\log_9y^4+\log_9x^{12}

Apply the product law:

\implies \log_2x^2z-\log_2y^2+\log_9x^{12}y^4

Apply the quotient law:

\implies \log_2\dfrac{x^2z}{y^2}+\log_9x^{12}y^4

Dimas [21]2 years ago
6 0

\\ \rm\Rrightarrow log_2z+2log_2x+4log_9y+12log_9x-2log_2y

  • log_a^b=bloga
  • log_a(bc)=log_a b+log_a c

So

\\ \rm\Rrightarrow log_2z+log_2x^2-log_2y^2+log_9y^4+log_9x^{12}

\\ \rm\Rrightarrow log_2(zx^2)-log_2y^2+log_9(y^4x^{12})

\\ \rm\Rrightarrow log_2\left(\dfrac{zx^2}{y^2}\right)+log_9(y^4x^{12})

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