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nekit [7.7K]
1 year ago
8

Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac

h solution is correct. A.y= 4x + 23 B. y = 6x C. y = 3x - 5 D. y = x E. y = -6 -
Mathematics
1 answer:
TiliK225 [7]1 year ago
6 0

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y= 1/6 x

put x = -6 and y = -1

-1 = -6/6

-1 = -1

LHS = RHS, so (-6 , -1) is a solution for that equation,

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Answer:

\displaystyle x > 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 3^{6x + 18} < 27^{3x}<em />

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Rewrite:                                                                                                             \displaystyle 3^{6x + 18} < 3^{3(3x)}
  2. Set:                                                                                                                     \displaystyle 6x + 18 < 3(3x)
  3. Factor:                                                                                                               \displaystyle 3(2x + 6) < 3(3x)
  4. [Division Property of Equality] Divide 3 on both sides:                                  \displaystyle 2x + 6 < 3x
  5. [Subtraction Property of Equality] Subtract 3x on both sides:                       \displaystyle -x + 6 < 0
  6. [Subtraction Property of Equality] Subtract 6 on both sides:                        \displaystyle -x < -6
  7. [Division Property of Equality] Divide -1 on both sides:                                 \displaystyle x > 6
8 0
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First, you want to divide both sides by 3 to isolate your variable. You get x^2 = 9. The square root of x^2 and 9 equals x = 3. 

x = 3 is your answer.
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