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2 years ago

Look at picture below

Mathematics

2 answers:

geniusboy [140]2 years ago

8 0

Answer:

I believe the answer you are looking for is C-√57

Mark brainliest :)

shtirl [24]2 years ago

3 0

A) Radical 185 is the correct answer

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A 5 pound Cartoon Clementine oranges is priced at $4.30 what is the price per pound of Clementine oranges

Y_Kistochka [10]

Answer:

The answer to your question is 0.86.

Step-by-step explanation:

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2 years ago

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A number is written with 10 zeros, 10 ones and 10 twos. Is it possible for it to be a perfect square ? Please help. I don’t unde

lora16 [44]

Answer:

i am going to help you to understand this problem. if it is written with 10 0s it will be the billion place. because of the ten ones it will be 0,000,010, and because of the ten two's, which is 20, it will be 0,000,030. and when i searched up on google, and watched an episode of number blocks, no, 30 is not a square number OR a cube number.

Step-by-step explanation:

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3 years ago

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3 years ago

A gym employee is paid monthly.after working for 3 months he had earned $4,500. To determine how much money he will make over a

Soloha48 [4]

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3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

Fencing required = 1586 m

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3 years ago