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Helen [10]
3 years ago
5

How many distinguishable permutations of the letters in DECEMBER are possible?

Mathematics
2 answers:
Lyrx [107]3 years ago
7 0
5 percent off the floor in the morning and
Genrish500 [490]3 years ago
7 0

#1

avatar+17746

+10

This can be calculated by using a fraction:

Count the number of letters in the word (in this case, 9) and create the numerator by the factorial of that number.

Since there are 9 letters in the word COMMITTEE, the numerator is  9!

Count the number of times each different letter is used and create the numerator by multiplying together the factorials of those numbers.  OK, that description may be clear as mud, so here's an example:

For COMMITTEE, the C is used once:  1!, the O is used once: 1!, the M is used twice: 2!, the I is used once: 1!, the T is used twice: 2!, and the E is used twice: 2!.

Putting these together, the denominator is  1!·1!·2!·1!·2!·2!  

So the answer is:  9! / [ 1!·1!·2!·1!·2!·2!  ]  =  45360

(A couple things about the denominator:  you really don't need to write down all the 1!, because their values are 1, but if you do, the sum of the numbers used in the denominator is equal to the number of letters in the word.)

Another example:  MISSISSIPPI  =  11! / [ 1!·4!·4!·2! ]


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Please help. Flow chart proof. I'll give brainliest
AveGali [126]

Step-by-step explanation:

Statement | Reason

CB=AB         Given

DBC=DBA   Given

DB = DB      Reflexive Property

/_\ DBC

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4 0
2 years ago
) Elise has put 5 cans (all of the same size) on her kitchen counter; 2 cans of vegetables, 2 cans of soup , and 1 can of peache
Anvisha [2.4K]

Answer:

0.7 = 70%.

Step-by-step explanation:

There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:

C(5,2) = 5!(3!*2!) = 5*4/2 = 10

To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:

There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:

C(3,2) = 3!/2! = 3

So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7

Then, the probability is 7 / 10 = 0.7 = 70%.

4 0
3 years ago
An object falls d meters in t seconds
harina [27]
You would take d times t seconds and find the answer
3 0
3 years ago
You and a friend are sharing a 3/8 bag of candy how much do you get equally
-BARSIC- [3]

Answer:

If both of them got the same amount of the bag then they each got 3/16 of the bag

4 0
3 years ago
What is true about the net of a pyramid? It will always contain exactly 1 triangle. It will always contain exactly 2 triangles.
Harrizon [31]

Answer:

im pretty sure its "D" It can contain any number of triangles greater than or equal to 4.

Step-by-step explanation:

7 0
3 years ago
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