Parallel lines have the same slope so for the new line we know m=-7 and the point (-4,6) we will substitute this info into our line to solve for b the y intercept.
Y=-7x+b
(6)=-7(-4)+b
6=28+b
6-28=28-28+b
-22=b
Now we put it all together using the slope m=-7 and the y intercept of -22
Y=-7x-22
Answer:
(-6, 36)
Step-by-step explanation:
The standard form: ax^2 + bx + c
In this case:
a is 1
b is 12
c is 0
Calculate -b / 2a. This is the x-coordinate of the vertex.
To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.
-12 / ( 2 x 1 )
-12 / 2
-6
You log -6 in the function
f(x) = x^2 + 12x
f(-6) = (-6)^2 + 12(-6)
= 36 + (-72)
= 36 - 72
= 36
I hope this
Answer:
x-intercept(s): (−1.9900717, 0)
y-intercept(s): (0, 52.5)
Step-by-step explanation:
To find the x-intercept, substitute in 
for 
and solve for 
. To find the y-intercept, substitute in for and solve for .
<u>x-intercept</u>
To find the x-intercept(s), substitute in for and solve for .
<u>y-intercept</u>
we have M is durectly porpotional to r^2
so M=(k)r^2
and when r=2, m=14
so 14=(k)(2)^2
k=14/4 =7/2
so when r=12
m= (7/2)(12)^2 =(7/2)(144) = 504
